我有几个像这样的字母数字字符串
listOfNum = ['000231512-n','1209123100000-n00000','alphanumeric0000', '000alphanumeric']
删除尾随零的期望输出是:
listOfNum = ['000231512-n','1209123100000-n','alphanumeric', '000alphanumeric']
前导尾随零的期望输出是:
listOfNum = ['231512-n','1209123100000-n00000','alphanumeric0000', 'alphanumeric']
删除前导零和尾随零的期望输出是:
listOfNum = ['231512-n','1209123100000-n', 'alphanumeric', 'alphanumeric']
目前我一直在这样做，如果有，请提出更好的方法:
listOfNum = ['000231512-n','1209123100000-n00000','alphanumeric0000', \
'000alphanumeric']
trailingremoved = []
leadingremoved = []
bothremoved = []
# Remove trailing
for i in listOfNum:
while i[-1] == "0":
i = i[:-1]
trailingremoved.append(i)
# Remove leading
for i in listOfNum:
while i[0] == "0":
i = i[1:]
leadingremoved.append(i)
# Remove both
for i in listOfNum:
while i[0] == "0":
i = i[1:]
while i[-1] == "0":
i = i[:-1]
bothremoved.append(i)
最佳答案
基本款呢
your_string.strip("0")
删除尾随和前导零？如果您只对删除尾随零感兴趣，请改用 .rstrip (而 .lstrip 仅用于前导零)。
更多信息见 doc.
你可以使用一些列表推导来获得你想要的序列:
trailing_removed = [s.rstrip("0") for s in listOfNum]
leading_removed = [s.lstrip("0") for s in listOfNum]
both_removed = [s.strip("0") for s in listOfNum]
关于python - 如何删除字符串中的前导零和尾随零？ Python，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/13142347/