我有一个对象数组,它有一个内部数组,需要过滤并根据两者的匹配返回数组。搜索是(输入)事件,它在每次按键时执行。
stackblitz 链接 stackblitz
list = [
{
id: 'abc',
data: [
{ key: '1', value: 'car' },
{ key: '2', value: 'bus' },
{ key: '3', value: 'bike' },
{ key: '4', value: 'truck' },
{ key: '5', value: 'jeep' },
],
},
{
id: 'def',
data: [
{ key: '1', value: 'car' },
{ key: '2', value: 'bicycle' },
{ key: '3', value: 'train' },
{ key: '4', value: 'aeroplane' },
{ key: '5', value: 'jeep' },
],
},
];
handleSearch = (event) => {
if (event.target.value.length > 0) {
const item = this.list[0].data.filter((items) =>
items.value.toLowerCase().includes(event.target.value.toLowerCase())
);
this.list[0].data = item;
} else {
this.list[0].data = this.orgList;
}
};
期待输出input = car
output = [
{
id: 'abc',
data: [
{ key: '1', value: 'car' },
],
},
{
id: 'def',
data: [
{ key: '1', value: 'car' },
],
},
];
input = truck
output =
[
{
id: 'abc',
data: [
{ key: '4', value: 'truck' },
],
},
];
最佳答案
const list = [{id: 'abc',data: [{ key: '1', value: 'car' },{ key: '2', value: 'bus' },{ key: '3', value: 'bike' },{ key: '4', value: 'truck' },{ key: '5', value: 'jeep' },],},{id: 'def',data: [{ key: '1', value: 'car' },{ key: '2', value: 'bicycle' },{ key: '3', value: 'train' },{ key: '4', value: 'aeroplane' },{ key: '5', value: 'jeep' },],},];
function search(arr, searchVal) {
return arr.map((item) => {
const data = item.data.filter(({ value }) => value === searchVal);
return { ...item, data };
})
.filter(({ data }) => data.length);
}
console.log(search(list, 'car'));
console.log(search(list, 'truck'));
.as-console-wrapper { max-height: 100% !important; top: 0 }
Angular demo
关于javascript - 如何从具有 2 个级别的 json 中搜索值作为来自两个对象的返回匹配项?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/69355921/