ios - 从应用程序打开电话 (iOS)

Question

有人可以告诉我如何通过单击按钮打开电话吗？我已经用它来进行 Safari 浏览并且它有效

  [[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"http://www.google.com"]];

Answer 1

您所需要的是:

NSString *phoneNumber = @"4167371111";

if([[UIApplication sharedApplication] canOpenURL:[NSURL URLWithString:@"tel://"]])
{    
    [[UIApplication sharedApplication] openURL:[NSURL URLWithString:[@"tel://" stringByAppendingString:[phoneNumber stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]]]];
}

如果您想做一些更高级的事情，例如查看用户是否调用了电话，您可以使用 CTCallCenter:

#import <CoreTelephony/CTCallCenter.h>
#import <CoreTelephony/CTCall.h>

//Create this property somewhere
@property (strong, nonatomic) CTCallCenter *callCenter;

NSString *phoneNumber = @"4167371111";

if([[UIApplication sharedApplication] canOpenURL:[NSURL URLWithString:@"tel://"]])
{
    self.callCenter = [[CTCallCenter alloc] init];
    [self.callCenter setCallEventHandler: ^(CTCall* call)
     {
         if ([call.callState isEqualToString: CTCallStateConnected]) {
             NSLog(@"Connected");
         } else if ([call.callState isEqualToString: CTCallStateDialing]) {
             NSLog(@"Dialing");
         } else if ([call.callState isEqualToString: CTCallStateDisconnected]) {
             NSLog(@"Disconnected");
         } else if ([call.callState isEqualToString: CTCallStateIncoming]) {
             NSLog(@"Incoming");
         }
     }];

    [[UIApplication sharedApplication] openURL:[NSURL URLWithString:[@"tel://" stringByAppendingString:[phoneNumber stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]]]];
}