我是 Python 新手,尝试读取 YAML 文件。根据其内容,我想创建 Python 对象。我正在使用 ruamel-yaml 库。 就我而言,也许我有 Python 类 Message、Signal 和 Signalgroup 等(请参阅示例文件)。
我的方法是读取 YAML 文件,检查每一行是否有给定的关键字,然后创建相关对象并用数据填充它。我认为这是“老派”方法,也许有更有效的方法来处理文件。
也许使用函数 register_class/rep。创建标签“from_yaml”,但由于键已编入索引,因此无法正常工作。
Message1:
Message2:
Message3:
还有更专业的方法吗?
# Yaml Testfile
- ModuleName: myTestModule
- Version: 1.0
- ModuleNumbers: [96,97,98,99]
- Message1:
Name: AO3_
DLC: 8
Signal1:
Name: Temperature
Length: 16
Signal2:
Name: AnalogOut3
Length: 16
SignalGroup1: #Comment
Name: app_fcex
Type: Bitfield
Signal1:
Name: drive_ready
Length: 1
Signal2:
Name: error_active
Length: 1
Signal3:
Name: warning_active
Length: 1
Signal3:
Name: Temperatur 2
Length: 8
ValueTable:
Name: TempStates
Item0:
Name: INIT
Value: 1
Item1:
Name: RUN
Value: 2
Item2:
Name: DONE
Value: 3
Item3:
Name: ERROR
Value: 4
- Message2:
name: AO2_
object: RX2
DLC: 8
最佳答案
我建议您在 YAML 文件中使用标签,并放弃使用名称为 Item1
、Item2
(替换为标记对象列表)的键。
很难看到数据的确切结构,但第一步可能是制作 YAML 文档(假设在文件 input.yaml
中:
- ModuleName: myTestModule
- Version: 1.0
- ModuleNumbers: [96,97,98,99]
- !Message
Name: AO3_
DLC: 8
Signal1:
Name: Temperature
Length: 16
Signal2:
Name: AnalogOut3
Length: 16
SignalGroup1: #Comment
Name: app_fcex
Type: Bitfield
Signal1:
Name: drive_ready
Length: 1
Signal2:
Name: error_active
Length: 1
Signal3:
Name: warning_active
Length: 1
Signal3:
Name: Temperatur 2
Length: 8
ValueTable:
Name: TempStates
items:
- !Item
Name: INIT
Value: 1
- !Item
Name: RUN
Value: 2
- !Item
Name: DONE
Value: 3
- !Item
Name: ERROR
Value: 4
- !Message
name: AO2_
object: RX2
DLC: 8
并加载:
import sys
import ruamel.yaml
class Item:
def __init__(self, name=None, value=None):
self.name = name
self.value = value
@classmethod
def from_yaml(cls, constructor, node):
for m in constructor.construct_yaml_map(node):
pass
return cls(m['Name'], m['Value'])
def __repr__(self):
return 'Item(name={.name}, value={.value})'.format(self, self)
class Message:
def __init__(self, name=None, DLC=None, object=None, signals=None):
self.name = name
self.dlc = DLC
self.object = object
self.signals = [] if signals is None else signals
@classmethod
def from_yaml(cls, constructor, node):
for m in constructor.construct_yaml_map(node):
pass
if 'Name' in m:
name = m['Name']
elif 'name' in m:
name = m['name']
else:
name = None
object = m['object'] if 'object' in m else None
if 'DLC' in m:
dlc = m['DLC']
else:
dlc = None
if 'signals' in m:
signals = m['signals']
elif 'Signal1' in m:
x = 1
signals = []
while True:
name = "Signal{}".format(x)
try:
signals.append(m[name])
except KeyError:
break
x += 1
else:
signals = None
return cls(name, dlc, object, signals)
def __repr__(self):
return 'Message(name={}, DLC={}, object={}, signals{})'.format(
self.name, self.dlc, self.object, '[...]' if self.signals else '[]',
)
yaml = ruamel.yaml.YAML(typ='safe')
yaml.register_class(Item)
yaml.register_class(Message)
with open('input.yaml') as fp:
data = yaml.load(fp)
上面对 key 可用性进行了一些但有限的检查(例如,规范化 !Message
的 Name
和 name
。
通过上面的 print('data')
给出(手工包装):
[{'ModuleName': 'myTestModule'},
{'Version': 1.0},
{'ModuleNumbers': [96, 97, 98, 99]},
Message(name=Signal4, DLC=8, object=None, signals[...]),
Message(name=AO2_, DLC=8, object=RX2, signals[])]
和 print(data[3].signals[2]['ValueTable']['items'][2])
给出:
Item(name=DONE, value=3)
当然应该酌情添加更多的类。
关于python - 读取 YAML 文件并创建 Python 对象,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/49029459/