sql-server - 在 Microsoft SQL Server 中从十六进制文字插入 varbinary 值

Question

我有一个 SpringBoot 应用程序，我使用 jdbcTemplate 向 mssql 插入一行

int numOfRowsAffected = remoteJdbcTemplate.update("insert into dbo.[ELCOR Resource Time Registr_]  "
                + "( [Entry No_], [Record ID], [Posting Date], [Resource No_], [Job No_], [Work Type], [Quantity], [Unit of Measure], [Description], [Company Name], [Created Date-Time], [Status] ) "
                + " VALUES (?,CONVERT(varbinary,?),?,?,?,?,?,?,?,?,?,?);",

                ELCORResourceTimeRegistr.getEntryNo(), 
                ELCORResourceTimeRegistr.getEntryNo()), 
                ELCORResourceTimeRegistr.getPostingDate(),
                ELCORResourceTimeRegistr.getResourceNo(), 
                jobNo,
                ELCORResourceTimeRegistr.getWorkType(), 
                ELCORResourceTimeRegistr.getQuantity(),
                ELCORResourceTimeRegistr.getUnitOfMeasure(), 
                ELCORResourceTimeRegistr.getDescription(),
                ELCORResourceTimeRegistr.getCompanyName(), 
                ELCORResourceTimeRegistr.getCreatedDate(), 
                0);

ELCORResourceTimeRegistr.getEntryNo() 的值是一个值为 0x00173672 的字符串

但是插入数据库的是<30007800 30003000 31003700 33003600 37003200>

ELCORResourceTimeRegistr.getEntryNo().getClass().getCanonicalName() => java.lang.String

Answer 1

documentation for the CONVERT function表示二进制类型的默认“样式”是 0:

Translates ASCII characters to binary bytes, or binary bytes to ASCII characters. Each character or byte is converted 1:1.

所以，

SELECT CONVERT(VARBINARY, '0x00173672') AS foo;

返回

foo
--------------------------------------------------------------
0x30783030313733363732

这是十六进制文字的 ASCII 字节值，而不是十六进制字节本身。为了让 CONVERT 解释十六进制文字，您需要使用样式 1，即

SELECT CONVERT(VARBINARY, '0x00173672', 1) AS foo;

返回

foo
--------------------------------------------------------------
0x00173672