react-native - react 导航 : Is it possible to goBack() or pop() with params?

Question

我正在使用 React Navigation (V2)，我有一个基本的屏幕设置，如下所示:

import {
  createDrawerNavigator,
  createStackNavigator,
  createSwitchNavigator
} from "react-navigation";

import DetailScreen from "../screens/DetailScreen";
import HomeScreen from "../screens/HomeScreen";
import LoginScreen from "../screens/LoginScreen";
import SettingsScreen from "../screens/SettingsScreen";

const StackNavigator = createStackNavigator({
  Home: { screen: HomeScreen },
  Detail: { screen: DetailScreen }
});

StackNavigator.navigationOptions = ({ navigation }) => {
  let drawerLockMode = "unlocked";
  if (navigation.state.index > 0) {
    drawerLockMode = "locked-closed";
  }
  return {
    drawerLockMode
  };
};

const DrawerNavigator = createDrawerNavigator({
  HomeStack: { screen: StackNavigator },
  Settings: { screen: SettingsScreen }
});

const Navigator = createSwitchNavigator(
  { LoginScreen, DrawerNavigator },
  { initialRouteName: "LoginScreen" }
);

export default Navigator;

在使用我的应用程序时，用户最终会进入 DetailScreen，做出一些选择，然后应该返回到 HomeScreen。我想在返回时将参数传递给 HomeScreen。不幸的是它看起来像pop()和 goBack()不接受任何参数。

我怎样才能返回屏幕并同时传递参数？

Answer 1

您可以使用 listeners屏幕并在那里触发刷新更改。

didFocus - 屏幕聚焦(如果有过渡，过渡 完成)

// In your component
componentDidMount () {
    this._onFocusListener = this.props.navigation.addListener('didFocus', (payload) => {
      // Update the component (API calls here)
    });
}