我正在尝试使用连接字符串调用与设备关联的方法。 我尝试使用其他语言提供的示例,我可以在设备中调用该方法。例如:灯的“setState”或“getState”。 但我无法在 iOS 中使用 swift 实现。
我尝试引用C示例来匹配参数参数要求。但我越来越 1. Func:sendHttpRequestDeviceMethod 行:337 Http 失败状态代码 400。 2. Func:IoTHubDeviceMethod_Invoke Line:492 发送设备方法调用的 HTTP 请求失败
var status :Int32! = 0
var deviceId = "simulated_device_one";
var methodName = "GetState";
var uint8Pointer:UnsafeMutablePointer<UInt8>!
uint8Pointer = UnsafeMutablePointer<UInt8>.allocate(capacity:8)
var size = size_t(10000)
var bytes: [UInt8] = [39, 77, 111, 111, 102, 33, 39, 0]
uint8Pointer?.initialize(from: &bytes, count: 8)
var intValue : UnsafeMutablePointer<UInt8>?
intValue = UnsafeMutablePointer(uint8Pointer)
var char: UInt8 = UInt8(20)
var charPointer = UnsafeMutablePointer<UInt8>(&char)
var prediction = intValue
let serviceClientDeviceMethodHandle = IoTHubDeviceMethod_Create(service_client_handle)
let payLoad = "test"
var responsePayload = ""
let invoke = IoTHubDeviceMethod_Invoke(serviceClientDeviceMethodHandle, deviceId, methodName, payLoad , 100, &status, &prediction,&size )
我想使用 IoTHubDeviceMethod_Invoke 调用设备中的方法
最佳答案
您可以下载我处理过的 View Controller 文件 from here
1.在 View 中创建连接已加载
// declaring your connection string you can find it in azure iot dashboard
private let connectionString = "Enter your connection String";
// creating service handler
private var service_client_handle: IOTHUB_SERVICE_CLIENT_AUTH_HANDLE!;
// handler for the method invoke
private var iot_device_method_handle:IOTHUB_SERVICE_CLIENT_DEVICE_METHOD_HANDLE!;
// In view did load establish the connection
service_client_handle = IoTHubServiceClientAuth_CreateFromConnectionString(connectionString)
if (service_client_handle == nil) {
showError(message: "Failed to create IoT Service handle", sendState: false)
}
- 创建方法调用函数
我根据提供的发送消息的演示创建了它
func openIothubMethodInvoke() -> Bool
{
print("In openIotHub method invoke")
let result: Bool;
iot_device_method_handle = IoTHubDeviceMethod_Create(service_client_handle);
let testValue : Any? = iot_device_method_handle;
if (testValue == nil) {
showError(message: "Failed to create IoT devicemethod", sendState: false);
result = false;
}
else
{
result = true;
}
return result;
}
- 调用方法调用
**这是调用方法的main函数
func methodInvoke()
{
let testValue : Any? = iot_device_method_handle;
if (testValue == nil && !openIothubMethodInvoke() ) {
print("Failued to open IoThub messaging");
}
else {
let size = UnsafeMutablePointer<Int>.allocate(capacity: 1)
let responseStatus = UnsafeMutablePointer<Int32>.allocate(capacity: 1)
// Payload is the main change it is like specifying the format
var payload = UnsafeMutablePointer<UnsafeMutablePointer<UInt8>?>.allocate(capacity: 1)
// if payload is not expected please send empty json "{}"
let result = IoTHubDeviceMethod_Invoke(iot_device_method_handle, "nameOfTheDeviceYouWantToCallOn", "MethodName", "{payload you want to send}", 100, responseStatus, payload , size)
// extracting the data from response
let b = UnsafeMutableBufferPointer(start: payload.pointee, count: size.pointee)
let data = Data(buffer: b)
let str = String(bytes: data, encoding: .utf8)
print(str)
do{
let value = try JSONSerialization.jsonObject(with: data, options: .allowFragments)
print(value)
}catch{
print(error)
}
}
}
关于ios - 如何使用azure iot sdk在ios中调用设备方法,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/57590121/