我在 React Redux 应用程序中为我的 UI 组件做这样的事情:
// Outer.js
import Inner from './path'
export const Outer = () => {
return (
<div>
...
<Inner />
...
</div>
)
}
// Inner.js
const param = ''
export const Inner = () => {
return (
<div>
<TextField
input={param}
onChange = {(param) => {
Function(param)
}}
/>
</div>
)
}
我还为 Outer.js 设置了一个容器组件:
// OuterContainer.js
import Outer from './path'
const mapStateToProps = (state) => {
paramToBeUpdated: ???
}
const mapDispatchToProps = (dispatch) => {
Function: (param) => dispatch(Function(param))
}
export default connect(mapStateToProps, mapDispatchToProps)(Outer)
我为此步骤创建的操作:
action/index.js
export const Function = (param) => (dispatch, getState) => {
dispatch({ type: 'FUNCTION', param })
}
我的 reducer 包含以下功能:
// reducer.js
export default reducer = (state="", action) => {
switch(action.type) {
case 'FUNCTION':
return {
...state,
param: action.param
}
...
}
}
我正在尝试从内部 UI 组件更新变量 paramToBeUpdated
的值。但它没有用。
Inner
和Outer
组件可以共享一个与Outer
相连的容器组件吗?
在不对当前设置做太多更改的情况下,我应该怎么做?是否可以避免创建一个新的内部容器,它基本上是外部容器的副本?
最佳答案
如果您无法将 Inner 与状态值和/或操作联系起来,那么您一定做错了什么,这是一个有效的示例:
const { Provider, connect } = ReactRedux;
const { createStore, applyMiddleware, compose } = Redux;
const { produce } = immer;
const initialState = {
value: '',
};
//action types
const CHANGE = 'CHANGE';
//action creators
const change = (value) => ({
type: CHANGE,
payload: value,
});
const reducer = (state, { type, payload }) => {
if (type === CHANGE) {
return produce(state, (draft) => {
draft.value = payload;
});
}
return state;
};
//creating store with redux dev tools
const composeEnhancers =
window.__REDUX_DEVTOOLS_EXTENSION_COMPOSE__ || compose;
const store = createStore(
reducer,
initialState,
composeEnhancers(
applyMiddleware(() => (next) => (action) =>
next(action)
)
)
);
//components
const Inner = connect((state) => state.value, {
Function: change,
})(({ Function, value }) => {
return (
<input
type="text"
value={value}
onChange={(e) => Function(e.target.value)}
/>
);
});
const Outer = () => {
return (
<div>
<Inner />
</div>
);
};
ReactDOM.render(
<Provider store={store}>
<Outer />
</Provider>,
document.getElementById('root')
);
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/16.8.4/umd/react.production.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react-dom/16.8.4/umd/react-dom.production.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/redux/4.0.5/redux.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react-redux/7.2.0/react-redux.min.js"></script>
<script src="https://unpkg.com/immer@7.0.5/dist/immer.umd.production.min.js"></script>
<div id="root"></div>
关于redux - 如何处理嵌套 React Redux 组件的 Action 调度,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/62809838/