c# - 有没有办法在 catch block 中编写 if 语句？

Question

我想要的是，如果没有引发异常，按钮 6 和 8 对用户可见。无论异常如何，finally block 都会运行，所以我不会把它放在那里

        if (worksheet == null)
            return;
        try
        {
            Range allo = worksheet.Rows.Cells[72, 2];
            allo.Value = AcceptableNoise.SelectedItem.ToString();
        }
        catch (Exception ee)
        {
            if (ee.Data != null)
            {
                _ = MessageBox.Show("One or more Options not selected " +
               "\n Eg: Confirm that Actuator Type is selected"/*ee.ToString()*/, "Selection Error", 
                MessageBoxButtons.OK, MessageBoxIcon.Hand);

            }
            else
            {
                button8.Visible = true;
                button6.Visible = true;
            }

        }
        
        
        finally
        {

            excel2.DisplayAlerts = false;
            excel2.ActiveWorkbook.Save();
            excel2.Application.Quit();
            excel2.Quit();


            /// = MessageBox.Show("You are done");
        }

Answer 1

这里是一些应该可以工作的代码示例。如果一切正确，将会出现按钮。除非他们会隐藏或保持隐藏状态。

try
{
    Range allo = worksheet.Rows.Cells[72, 2];
    allo.Value = AcceptableNoise.SelectedItem.ToString();
    button8.Visible = true;
    button6.Visible = true;
}
catch (Exception ee)
{
    MessageBox.Show("One or more Options not selected " +
        "\n Eg: Confirm that Actuator Type is selected"/*ee.ToString()*/, 
        "Selection Error", 
        MessageBoxButtons.OK, MessageBoxIcon.Hand);

    button8.Visible = false;
    button6.Visible = false;
}               
finally
{
    excel2.DisplayAlerts = false;
    excel2.ActiveWorkbook.Save();
    excel2.Application.Quit();
    excel2.Quit();

    MessageBox.Show("You are done");
}

但有一个条件非常重要 - button8.Visible = true 之前的代码必须在需要时抛出异常。如果没有，按钮无论如何都会出现。