我有一个包含数字的字符串列表,但我找不到对它们进行排序的好方法。
例如我得到这样的东西:
something1
something12
something17
something2
something25
something29
使用 sort()
方法。
我知道我可能需要以某种方式提取数字然后对列表进行排序,但我不知道如何以最简单的方式进行。
最佳答案
也许您正在寻找 human sorting (也称为 natural sorting):
import re
def atoi(text):
return int(text) if text.isdigit() else text
def natural_keys(text):
'''
alist.sort(key=natural_keys) sorts in human order
http://nedbatchelder.com/blog/200712/human_sorting.html
(See Toothy's implementation in the comments)
'''
return [ atoi(c) for c in re.split(r'(\d+)', text) ]
alist=[
"something1",
"something12",
"something17",
"something2",
"something25",
"something29"]
alist.sort(key=natural_keys)
print(alist)
产量
['something1', 'something2', 'something12', 'something17', 'something25', 'something29']
PS。我已将答案更改为使用 Toothy 的自然排序实现(发表在评论 here 中),因为它比我原来的答案快得多。
如果您希望使用 float 对文本进行排序,则需要将正则表达式从匹配整数(即 (\d+)
)的正则表达式更改为 a regex that matches floats :
import re
def atof(text):
try:
retval = float(text)
except ValueError:
retval = text
return retval
def natural_keys(text):
'''
alist.sort(key=natural_keys) sorts in human order
http://nedbatchelder.com/blog/200712/human_sorting.html
(See Toothy's implementation in the comments)
float regex comes from https://stackoverflow.com/a/12643073/190597
'''
return [ atof(c) for c in re.split(r'[+-]?([0-9]+(?:[.][0-9]*)?|[.][0-9]+)', text) ]
alist=[
"something1",
"something2",
"something1.0",
"something1.25",
"something1.105"]
alist.sort(key=natural_keys)
print(alist)
产量
['something1', 'something1.0', 'something1.105', 'something1.25', 'something2']
关于python - 如何正确排序带有数字的字符串?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/5967500/