当我使用表单时,我有那个 URL
view-source:http://teory.loc/realty/appartment_rent/day?city=&district=&cost_up=29999&cost_to=333333&rooms_up=&rooms_to=&area_up=&area_to=&floor_up=&floor_to=
例如
为了处理这个 URL,我使用了那个代码
public static function search($paginate, $condotions = null, $order = null){
return AppartmentRentDay::where(function ($query) use ($condotions){
foreach ($condotions as $key => $value){
if($value){
$parametrs = [];
if(substr($key,-3) == "_up"){
$parametrs[0] = substr($key,0,-3);
$parametrs[1] = '>=';
}elseif (substr($key,-3) == "_to"){
$parametrs[1] = '<=';
$parametrs[0] = substr($key,0,-3);
}else{
$parametrs[0] = $key;
$parametrs[1] = '=';
}
$query->where($parametrs[0], $parametrs[1], $value);
}
}
})->paginate($paginate);
}
分页工作正常,但
{{ $info->links() }}
是什么给了那个 hrefs<ul class="pagination">
<li class="disabled"><span>«</span></li>
<li class="active"><span>1</span></li>
<li><a href="http://teory.loc/realty/appartment_rent/day?page=2">2</a></li>
<li><a href="http://teory.loc/realty/appartment_rent/day?page=2" rel="next">»</a></li>
</ul>
这不正确,如何为此href添加我的get参数?
请给我一些信息
泰
Laravel 5.5
最佳答案
您可以将现有参数附加到链接中,如下所示:
AppartmentRentDay::where(...)->paginate($paginate)->appends(request()->except('page'));
关于php - Laravel 分页添加获取参数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/46570698/