当我为 JSON 文件创建模型时，出现这两个错误。
1) 我在 AreaData 结构中遇到了符合错误
2) “AnyObject 不能用作符合协议(protocol) Decodable 的类型，因为 Decodable 具有静态要求”初始化程序中的错误。
我尝试了多种方法，但找不到正确的解决方案。如何为这个嵌套/复杂的 JSON 制作合适的模型？
这是我的 JSON 文件。这个数据是嵌套的
[
{
"ID": "01",
"Name": "Area 01",
"parentId": null,
"sublevel": [
{
"ID": "01-01",
"Name": "Building 01",
"On": "",
"Off": "",
"parentId": "01",
"sublevel": [
{
"ID": "01-01-01",
"Name": "Flat 01",
"On": "",
"Off": "",
"parentId": "01-01",
"sublevel": []
}
]
},
{
"ID": "01-02",
"Name": "Building 02",
"On": "01",
"Off": "03",
"parentId": "01",
"sublevel": [
{
"ID": "01-02-01",
"Name": "Flat 01",
"On": "",
"Off": "",
"parentId": "01-02",
"sublevel": []
},
{
"ID": "01-02-02",
"Name": "Flat 02",
"On": "01",
"Off": "02",
"parentId": "01-02",
"sublevel": []
},
{
"ID": "01-02-03",
"Name": "Flat 03",
"On": "02",
"Off": "12",
"parentId": "01-02",
"sublevel": [
{
"ID": "01-02-03-01",
"Name": "Room 01",
"On": "",
"Off": "",
"parentId": "01-02-03",
"sublevel": []
},
{
"ID": "01-02-03-02",
"Name": "Room 02",
"On": "",
"Off": "",
"parentId": "01-02-03",
"sublevel": []
},
{
"ID": "01-02-03-03",
"Name": "Room 03",
"On": "02",
"Off": "03",
"parentId": "01-02-03",
"sublevel": []
},
{
"ID": "01-02-03-04",
"Name": "Room 04",
"On": "",
"Off": "",
"parentId": "01-02-03",
"sublevel": []
},
{
"ID": "01-02-03-05",
"Name": "Room 05",
"On": "01",
"Off": "",
"parentId": "01-02-03",
"sublevel": []
}
]
},
{
"ID": "01-02-04",
"Name": "Flat 04",
"On": "12",
"Off": "03",
"parentId": "01-02",
"sublevel": []
},
{
"ID": "01-02-05",
"Name": "Flat 05",
"On": "02",
"Off": "",
"parentId": "01-02",
"sublevel": []
}
]
},
{
"ID": "01-03",
"Name": "Building 03",
"On": "02",
"Off": "01",
"parentId": "01",
"sublevel": []
},
{
"ID": "01-04",
"Name": "Building 04",
"On": "",
"Off": "",
"parentId": "01",
"sublevel": []
}
]
}
]
这是我的模型类
import Foundation
struct AreaData : Codable {
let iD : String?
let name : String?
let parentId : AnyObject?
let sublevel : [Sublevel]?
enum CodingKeys: String, CodingKey {
case iD = "ID"
case name = "Name"
case parentId = "parentId"
case sublevel = "sublevel"
}
init(from decoder: Decoder) throws {
let values = try decoder.container(keyedBy: CodingKeys.self)
iD = try values.decodeIfPresent(String.self, forKey: .iD)
name = try values.decodeIfPresent(String.self, forKey: .name)
parentId = try values.decodeIfPresent(AnyObject.self, forKey: .parentId)
sublevel = try values.decodeIfPresent([Sublevel].self, forKey: .sublevel)
}
}
struct Sublevel : Codable {
let on : String?
let iD : String?
let name : String?
let off : String?
let parentId : String?
let sublevel : [Sublevel]?
enum CodingKeys: String, CodingKey {
case on = "On"
case iD = "ID"
case name = "Name"
case off = "Off"
case parentId = "parentId"
case sublevel = "sublevel"
}
init(from decoder: Decoder) throws {
let values = try decoder.container(keyedBy: CodingKeys.self)
on = try values.decodeIfPresent(String.self, forKey: .on)
iD = try values.decodeIfPresent(String.self, forKey: .iD)
name = try values.decodeIfPresent(String.self, forKey: .name)
off = try values.decodeIfPresent(String.self, forKey: .off)
parentId = try values.decodeIfPresent(String.self, forKey: .parentId)
sublevel = try values.decodeIfPresent([Sublevel].self, forKey: .sublevel)
}
}
最佳答案
尝试这个，
struct AreaDataModel: Codable {
let id, name: String
let parentID: String? // AnyObject can't conform to Encodable protocol .
let sublevel: [Sublevel]
enum CodingKeys: String, CodingKey {
case id = "ID"
case name = "Name"
case parentID = "parentId"
case sublevel
}
}
// MARK: - Sublevel
struct Sublevel: Codable {
let id, name, on, off: String
let parentID: String
let sublevel: [Sublevel]
enum CodingKeys: String, CodingKey {
case id = "ID"
case name = "Name"
case on = "On"
case off = "Off"
case parentID = "parentId"
case sublevel
}
}
typealias AreaData = [AreaDataModel]
I recommend this tool simple and fast .
关于json - 类型 'AreaData' 不符合协议(protocol) 'Encodable'，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/57176854/