php - 自然语言处理的正则表达式 "does not contain"模式问题

Question

链接到 regex101

I am implementing a simple NLP algo. I have already implemented the solution looping over the raw string to assist the regex, but now I want to see if I can do it in pure regex.

我不知道如何让“构建”小组尊重 future 的负面看法。我正在 try catch [“自然语言处理”算法] 任何帮助将不胜感激，谢谢😀

$subject_string = <<<'subject_string'
Projects I've built & Plan to build. HackMatch.io (May 2020 onward), 
As of October 2020, I intend to start implementing "Natural Language Processing" algorithms 
in PHP when I have time. I'll then use PHP to upload the results to big data tech (e.g. BigQuery) 
to create some data visualizations.
subject_string;

$pattern = <<<'pattern'
/\b(?'verb'build|make|implementing)
(?'build'.+?(?!build|make|implementing)) 
(?=\bin\b|\bon\b)
(?:build|make|implementing)??/ix
pattern;

preg_match_all($pattern, $subject_string, $matches)

Answer 1

您可以使用

/\b(?'verb'build|make|implementing)\s*
(?'build'(?:(?!(?&verb)).)*?) 
(?=\s*\b(?:in|on)\b)/ixs

见 regex demo . 详情 :

\b - 一个词边界

(?'verb'build|make|implementing) - 组“动词”:括号内的词之一

\s* - 零个或更多空格

(?'build'(?:(?!(?&verb)).)*?) - 组“build”:任何字符，零次或多次出现，但尽可能少，不会开始“动词”组中定义的任何字符序列

\s* - 零个或更多空格

(?=\b(?:in|on)\b) - 与紧跟在整个单词后面的位置匹配的正向前瞻 in或 on .