如何使用 Jenkins 声明式语法管道将 JSON 对象捕获为美化字符串?
pipeline {
agent any
stages {
stage( "Set up" ) {
steps {
script {
hostname = "bld-machine"
reply_email = "jenkins@${hostname}.company.com"
actor_email = "user@company.com"
status_json = initStatusJson()
}
}
}
/** Try figure out the difference between "global" and "env." variables. */
stage( "Capture variables" ) {
steps {
script {
status_json.env["var"] = "${env.var}" as String
status_json.env["var2"] = "${var}" as String
}
}
}
}
post {
always {
script {
def pretty_json = writeJSON( returnText: true, json: status_json )
}
emailext( subject: "CI/CD | ${currentBuild.currentResult}",
from: "${reply_email}",
to: "${actor_email}",
mimeType: "text/plain",
body: "${pretty_json}" )
}
}
}
def initStatusJson() {
def json_obj = readJSON text: '{}'
json_obj.job = readJSON text: '{}'
json_obj.env = [:]
json_obj.job.name = "${JOB_BASE_NAME}" as String
json_obj.job.number = "${BUILD_ID}" as String
json_obj.job.server = "${JENKINS_URL}" as String
json_obj.job.visualization = "${JENKINS_URL}/blue/organizations/jenkins/${JOB_BASE_NAME}/detail/${JOB_BASE_NAME}/${BUILD_ID}/pipeline" as String
return json_obj
}
def pretty_json =...
上面 Jenkinsfile 中的语句触发以下错误:WARNING: Unknown parameter(s) found for class type WARNING: Unknown parameter(s) found for class type 'org.jenkinsci.plugins.pipeline.utility.steps.json.WriteJSONStep': returnText
[Pipeline] }
[Pipeline] // script
Error when executing always post condition:
java.lang.IllegalArgumentException: You have to provided a file for writeJSON.
at org.jenkinsci.plugins.pipeline.utility.steps.json.WriteJSONStepExecution.run(WriteJSONStepExecution.java:61)
at org.jenkinsci.plugins.pipeline.utility.steps.json.WriteJSONStepExecution.run(WriteJSONStepExecution.java:43)
at org.jenkinsci.plugins.workflow.steps.SynchronousNonBlockingStepExecution.lambda$start$0(SynchronousNonBlockingStepExecution.java:47)
at java.util.concurrent.Executors$RunnableAdapter.call(Executors.java:511)
at java.util.concurrent.FutureTask.run(FutureTask.java:266)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1149)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:624)
at java.lang.Thread.run(Thread.java:748)
我试过的:
def pretty_json = writeJSON( returnText: true, json: status_json )
声明的灵感来自这些资源:Jenkinsfile pipeline construct JSON object and write to file
https://www.jenkins.io/doc/pipeline/steps/pipeline-utility-steps/#writejson-write-json-to-a-file-in-the-workspace
def pretty_json = writeJSON returnText: true, json: status_json
这导致了相同的错误。status_json.toString()
返回一个有效但未美化的 JSON 字符串。def pretty_json = JsonOutput.toJson(status_json)
基于 Create JSON strings from Groovy variables in Jenkins Pipeline ,并生成此错误:Error when executing always post condition:
groovy.lang.MissingPropertyException: No such property: JsonOutput for class: groovy.lang.Binding
def pretty_json = groovy.json.JsonOutput.prettyPrint(status_json)
基于 https://gist.github.com/osima/1161966 ,它产生了这个错误:Error when executing always post condition:
groovy.lang.MissingMethodException: No signature of method: java.lang.Class.prettyPrint() is applicable for argument types: (net.sf.json.JSONObject)
更新:尝试@daggett 的解决方案如下:
post {
always {
script {
def pretty_json = status_json.toString(2)
}
emailext( subject: "CI/CD | ${currentBuild.currentResult}",
from: "${reply_email}",
to: "${actor_email}",
mimeType: "text/plain",
body: "${pretty_json}" )
}
}
...还尝试了一些变体,例如 pretty_json = ...
(而不是 def pretty_json = ...
)并移动 pretty_json
script{...}
之外的赋值范围......但没有一个工作。内
script{...}
上下文,.toString(2)
产生了这个错误:Scripts not permitted to use method net.sf.json.JSON toString int.
外script{...}
上下文,它生成了我解释为“语法错误”的内容:WorkflowScript: 79: Expected a step @ line 79, column 7.
pretty_json = status_json.toString(2)
最佳答案
根据上次错误信息
groovy.lang.MissingMethodException:
No signature of method: java.lang.Class.prettyPrint()
is applicable for argument types: (net.sf.json.JSONObject)
您有 net.sf.json.JSONObject
在 status_json
多变的。that's really strange - seems you are getting
status_json
not in a standard way for jenkins
但是根据这个类的文档
http://json-lib.sourceforge.net/apidocs/jdk15/net/sf/json/JSONObject.html#toString(int)
只需执行以下操作即可制作漂亮的 json:
def pretty_json = status_json.toString(2)
如果您有
Scripts not permitted to use method XYZ
异常(exception):出于安全原因,jenkins 中禁用了许多非标准方法。
请参阅此答案以解决此类问题:https://stackoverflow.com/a/39412951/1276664
最后 - 您问题中的几乎每个案例都应该有效:
writeJSON( returnText: true, json: status_json )
:更新 pipeline-utility-steps jenkins 插件到最新版本支持
returnText
范围...
JsonOutput.toJson(status_json)
:JsonOutput类(class)位于 groovy.json
包裹。你可以在 t 导入这个包剧本开头
import groovy.json
或者这样称呼它:groovy.json.JsonOutput.toJson(status_json)
.请注意,此方法返回非格式化的 json。groovy.json.JsonOutput.prettyPrint(status_json)
: 查看 JsonOutput.prettyPrint 的文档- 可以为字符串而不是对象调用它。所以这可以工作:groovy.json.JsonOutput.prettyPrint(status_json.toString())
但仅在 status_json.toString()
的情况下返回一个有效的 json 和 JsonOutput.prettyPrint
允许在 jenkins admin 中调用。关于json - Groovy/ Jenkins : how to prettify json string?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/67829146/