ios - 模仿 UITextView 的默认双击行为

Question

有谁知道当用户在 UITextView 中用两根手指点击时会调用什么方法？

当用户用两根手指点击时，会选择段落中的整个文本。我想以编程方式实现相同的选择，以使此段落选择在我的自定义单击手势方法中可用。

Answer 1

从 UITextView 双击手势识别器的默认行为来看，我认为 selectAll: 是被调用来处理文本选择的方法。同样，您可以通过在现有的 tapTextViewGesture: 方法中利用 selectAll: 来强制 TextView 在识别单击手势识别器时选择文本(如评论中所述) .

如果您希望文本选项像响应默认的双击手势识别器(即剪切、复制、粘贴等)一样自动显示，请将 selectAll: 设置为 self :

- (IBAction)tapTextViewGesture:(id)sender {
    [self.textView selectAll:self]; 
}

否则，要简单地选择文本而不显示菜单，请将其设置为nil:

- (IBAction)tapTextViewGesture:(id)sender {
    [self.textView selectAll:nil]; 
}

已更新

正如评论中的OP所指出的，UITextView双击手势识别器最初只会导致选择单个段落。

首先，从当前光标位置显示编辑菜单:

// Access the application's shared menu
UIMenuController *menu = [UIMenuController sharedMenuController];

// Calculate the cursor's position within the superview
// and convert it to a CGRect
CGPoint cursorPosition = [self.textView caretRectForPosition:self.textView.selectedTextRange.start].origin;
CGPoint cursorPositionInView = [self.textView convertPoint:cursorPosition toView:self.view];
CGRect menuRect = CGRectMake(cursorPositionInView.x, cursorPositionInView.y, 0, 0);

// Show the menu from the cursor's position
[menu setTargetRect:menuRect inView:self.view];
[menu setMenuVisible:YES animated:YES];

然后选择当前段落，这是我的建议:

// Break the text into components separated by the newline character
NSArray *paragraphs = [self.textView.text componentsSeparatedByString:@"\n"];

// Keep a tally of the paragraph character count
int characterCount = 0;

// Go through each paragraph
for (NSString *paragraph in paragraphs) {

    // If the total number of characters up to the end
    // of the current paragraph is greater than or
    // equal to the start of the textView's selected
    // range, select the most recent paragraph and break
    // from the loop
    if (characterCount + paragraph.length >= self.textView.selectedRange.location) {
        [self.textView setSelectedRange:NSMakeRange(characterCount, paragraph.length)];
        break;
    }

    // Increment the character count by adding the current
    // paragraph length + 1 to account for the newline character
    characterCount += paragraph.length + 1;
}