正则表达式和 sed 在多行 block 中查找字符串 block ，直到它以空格结尾

Question

我 try catch 这些字符串块并使用正则表达式和 sed 对它们进行注释。
每个块用空格分隔

some text here 
some text here 

AppServer1:
  name: ${AppServer1.name}
  ip: ${AppServer1.ip}
   
some text here 
some text here 

AppServer2:
  name: ${AppServer1.name}
  ip: ${AppServer1.ip}

some text here 
some text here 
   

我尝试使用这个正则表达式:

sed E '/./{H;1h;$!d} ; x ; s/[^\$AppServer1](AppServer1)/#\1/gi'

但结果是:

 #AppServer1:
      name: $#{AppServer1.name}
      ip: $#{AppServer1.ip}

我在这里缺少评论完整字符串的内容:

#AppServer1:
#      name: ${AppServer1.name}
#      ip: ${AppServer1.ip}

Answer 1

使用 gnu-sed ， 你可以这样做:

sed '/^AppServer1/I{:a; /^[[:blank:]]*$/!{s/.*/#&/; n; ba;} }' file

some text here
some text here

#AppServer1:
#  name: ${AppServer1.name}
#  ip: ${AppServer1.ip}

some text here
some text here

AppServer2:
  name: ${AppServer1.name}
  ip: ${AppServer1.ip}

some text here
some text here

详情:

/^AppServer1/I : 搜索 AppServer1不区分大小写

{ : 块启动

:a : 制作标签a

/^[[:blank:]]*$/!如果一行不是空行

{s/.*/#&/; n; ba;} :在每一行前面加上 # , 阅读下一行并转到标签 a

} : 座结束

使用 awk你可以这样做:

awk '/^AppServer1/ {b=1} b && !NF {b=0} b {$0 = "#" $0} 1' file

some text here
some text here

#AppServer1:
#  name: ${AppServer1.name}
#  ip: ${AppServer1.ip}

some text here
some text here

AppServer2:
  name: ${AppServer1.name}
  ip: ${AppServer1.ip}

some text here
some text here