python - 如何创建字典的优先级列表

Question

名单如下

偏好字典低于

如果除 type 之外的所有键和值那么将相同..

需要比较type在偏好字典中最高顺序的每个列表中

输出是最高阶字典的列表

list_ = [
  {
    "id": "11",
    "name": "son",
    "email": "n@network.com",
    "type": "Owner"
  },
      {
    "id": "11",
    "name": "son",
    "email": "n@network.com",
    "type": "Manager"
  },
{
    "id": "21",
    "name": "abc",
    "email": "abc@network.com",
    "type": "Employ"
  },
{
    "id": "21",
    "name": "abc",
    "email": "abc@network.com",
    "type": "Manager"
  }
]

偏好词典 = {'Owner': 1, 'Manager':2, 'employ':3, 'HR': 4 }我预期的输出字典如下

[{'id': '11', 'name': 'son', 'email': 'n@network.com', 'type': 'Owner'},
{'id':'21','name': 'abc','email': 'abc@network.com','type': 'Manager'}]

new_list = []
for each in list_:
    if each['type'] in priority.keys():
        if each['id'] not in new_list:
            new_list.append(each)

Answer 1

你可以简单地做 src.sort(key = lambda x : preference[x["type"]])并且您的列表将被排序。