c - 理解指针数组

Question

我正在做这样的事情；

int main()
{
    int *b[2], j;
    for (j = 0; j < 2; j++)
    {
        b[j] = (int *)malloc(12 * sizeof(int));
    } 
    return 0;
}

请告诉我这条指令的真正含义是什么？如何将此指针数组传递给函数以访问 *(B[0]+1),*(B[1]+1) 等值？

Answer 1

int main(void)
{
    int *b[2], j; // initialization of an array of pointers to integers (size = 2)
    for (j = 0; j < 2; j++) // for each of the pointers 
    {
        b[j] = malloc(12 * sizeof (int)); // allocate some space = 12 times size of integer in bytes (usually 4)
    } 
    return 0;
}

如果你想将此数组传递给函数，只需传递 b

foo(b);