我在这里找不到错误,我该如何解决这个问题?
$db2 = DB::connection('sqlsrv')->table('Checkinout')
->join('Z_MemRecord','Checkinout.Userid','=','Z_MemRecord.uid')
->select(DB::raw("FORMAT(MAX (Checkinout.CheckTime), 'hh:mm tt') AS OffTime, FORMAT (min(Checkinout.CheckTime), 'hh:mm tt') AS Ontime, Checkinout.Userid,Z_MemRecord.Uname,FORMAT (Checkinout.CheckTime, 'MMM dd yyyy') as dates,FORMAT (Checkinout.CheckTime, 'dddd') as hour"))
->groupBy(DB::raw("Convert(Date, Checkinout.CheckTime),Checkinout.Userid,Z_MemRecord.Uname,FORMAT(Checkinout.CheckTime, 'MMM dd yyyy'),FORMAT (Checkinout.CheckTime, 'dddd')"));
$result = DB::connection('mysql')->table('netdoc')->insert(['Logid' => $db2['Checkinout.Userid'] ,'name'=> $db2['Z_MemRecord.Uname'],'dates' => $db2['dates'],'day'=>$db2['hour'],'Ontime' => $db2['Ontime'],'Offtime' => $db2['OffTime']]);
dd($db2);
最佳答案
方法groupBy()
返回一个QueryBuilder
,将其转换为数组,调用get()
来接收行数组。
->groupBy(...)
->get();
您需要处理返回多行的查询,因此一个快速解决方案是使用 foreach()
遍历 db2。
foreach ($db2 as $row) {
$row = (array) $row;
$result = DB::connection('mysql')
->table('netdoc')
->insert(['Logid' => $row['Checkinout.Userid'] ,'name'=> $row['Z_MemRecord.Uname'],'dates' => $row['dates'],'day'=>$row['hour'],'Ontime' => $row['Ontime'],'Offtime' => $row['OffTime']]);
}
关于php - 无法将 Illuminate\Database\Query\Builder 类型的对象用作数组,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/59856073/