gtk - 使用 glib.string.escape() 时如何转义特殊字符

Question

由于glib.string.escape()的文档

Escapes the special characters '\b', '\f', '\n', '\r', '\t', '\v', '\' and '"' in the string source by inserting a '\' before them.

Additionally all characters in the range 0x01-0x1F (everything below SPACE) and in the range 0x7F-0xFF (all non-ASCII chars) are replaced with a '\' followed by their octal representation. Characters supplied in exceptions are not escaped.

现在我想要不 eacape“0x7F-0xFF”字符。如何编写异常(exception)部分？

我的示例代码不起作用。

            shellcmd = "bash -c \""+file.get_string(title,"List").escape("0x7F-0xFF")+"\"";
            print("shellcmd: %s\n", shellcmd);
            Process.spawn_command_line_sync (shellcmd,
            out ls_stdout, out ls_stderr, out ls_status);
            if(ls_status!=0){ list = ls_stderr.split("\n"); }
            else{ list = ls_stdout.split("\n"); }

---

这有效。

shellcmd = "bash -c \""+file.get_string(title,"Check").replace("\"","\\\"")+"\"";

Answer 1

实际上，您必须将字符 0x7f 放入 exceptions 参数中的 0xff 中。所以类似:

shellcmd = "bash -c \""+file.get_string(title,"List").escape("\x7F\x80\x81\x82…\xfe\xff")+"\"";

您需要手动列出它们。

更广泛地查看您的代码，您似乎正在构建一个要运行的命令。这是一个非常糟糕的主意，你绝对不应该这样做。它对code injection敞开大门。 。使用 Process.spawn_sync() 并向其传递一个参数向量。