python - 函数重复十次而不是一次 - Pygame Zero

Question

我在 Pygame Zero 中编写了一个简单的赛车游戏。这来自 MagPi“使用 Raspberry Pi 进行复古游戏”一书。我是一名初级程序员，所以我可能会问一个明显的问题。我想制作关卡。每 100 score , level + 1. 赢得 10 个级别。

感兴趣的领域可能是我的 draw()功能:

    global gameStatus, level
    screen.fill((128, 128, 128))
    if gameStatus == 0:
        car.draw()
        b = 0
        while b < len(trackLeft):
            trackLeft[b].draw()
            trackRight[b].draw()
            b += 1
        screen.draw.text("Score: " + str(score), (50, 30), color="black")
        if score % 100 == 0:
            check_levels()
        screen.draw.text("Level: " + str(level), (50, 50), color="black")
    if gameStatus == 1:
        screen.blit('rflag', (318, 268))
    if gameStatus == 2:
        screen.blit('cflag', (318, 268))

和我的 level_up()功能:

    global level
    if level <= 10:
        level += 1
    if level == 10:
        gameStatus == 2

每制作一首曲子就计分，得分高一个。

我的问题 : 当我达到 100 score , 级别加 10，而不是加 1。我不知道似乎发生了什么。可能是因为每个分数都有一些 FPS/tick，并且随着关卡每刻更新一次，似乎当分数在 100 上停留大约 10 个刻时，级别每刻更新一次？

由于我的程序很短，我将继续发布所有代码:

import time
from random import randint
import pygame
import pgzrun


WIDTH = 700
HEIGHT = 800


car = Actor("racecar")
car.pos = 250, 700
SPEED = 4
trackLeft = []
trackRight = []
trackCount = 0
trackPosition = 250
trackWidth = 120
trackDirection = False
gameStatus = 0
score = 0
level = 1


def draw():
    global gameStatus, level
    screen.fill((128, 128, 128))
    if gameStatus == 0:
        car.draw()
        b = 0
        while b < len(trackLeft):
            trackLeft[b].draw()
            trackRight[b].draw()
            b += 1
        screen.draw.text("Score: " + str(score), (50, 30), color="black")
        if score % 100 == 0:
            check_levels()
        screen.draw.text("Level: " + str(level), (50, 50), color="black")
    if gameStatus == 1:
        screen.blit('rflag', (318, 268))
    if gameStatus == 2:
        screen.blit('cflag', (318, 268))


def update():
    global gameStatus, trackCount
    if gameStatus == 0:
        if keyboard.left: car.x -= 2
        if keyboard.right: car.x += 2
        update_track()


def make_track():
    global trackCount, trackLeft, trackRight, trackPosition, trackWidth, score
    trackLeft.append(Actor("barrier", pos=(trackPosition - trackWidth, 0)))
    trackRight.append(Actor("barrier", pos=(trackPosition + trackWidth, 0)))
    trackCount += 1
    score += 1


def update_track():
    global trackCount, trackPosition, trackDirection, trackWidth, gameStatus
    b = 0
    while b < len(trackLeft):
        if car.colliderect(trackLeft[b]) or car.colliderect(trackRight[b]):
            gameStatus = 1
        trackLeft[b].y += SPEED
        trackRight[b].y += SPEED
        b += 1
    if trackLeft[len(trackLeft) - 1].y > 32:
        if trackDirection == False: trackPosition += 16
        if trackDirection == True: trackPosition -= 16
        if randint(0, 4) == 1: trackDirection = not trackDirection
        if trackPosition > 700 - trackWidth: trackDirection = True
        if trackPosition < trackWidth: trackDirection = False
        make_track()


def check_levels():
    global level
    if level <= 10:
        level += 1
    if level == 10:
        gameStatus = 2


make_track()


pgzrun.go()

Answer 1

您必须在分数更新时进行级别检查。注意，draw执行得更频繁，然后分数更新，所以 if score % 100 == 0:多次满足并且级别增加不止一次:

def draw():
    global gameStatus, level
    screen.fill((128, 128, 128))
    if gameStatus == 0:
        # [...]

        screen.draw.text("Score: " + str(score), (50, 30), color="black")

        # DELETE <--------------------------
        #if score % 100 == 0:
        #    check_levels()

        screen.draw.text("Level: " + str(level), (50, 50), color="black")

def make_track():
    #[...]
    trackCount += 1
    score += 1

    # ADD <-----------------------------
    if score % 100 == 0:
        check_levels()

此外，您的游戏会在一段时间后滞后，因为列表 trackLeft和 trackRight正在不断增长。从列表中删除底部窗口之外的障碍:

def make_track():
    global trackCount, trackLeft, trackRight, trackPosition, trackWidth, score
    trackLeft.append(Actor("barrier", pos=(trackPosition - trackWidth, 0)))
    trackRight.append(Actor("barrier", pos=(trackPosition + trackWidth, 0)))

    # remove barriers which are out of screen
    if trackLeft[0].y >= HEIGHT:
        del trackLeft[0]
    if trackRight[0].y >= HEIGHT:
        del trackRight[0]

    trackCount += 1
    score += 1
    if score % 100 == 0:
        check_levels()