我的 Rocket API 中有以下登录 POST 端点处理程序:
#[post("/login", data = "<login_form>")]
pub fn login_validate(login_form: Form<LoginForm>) -> Result<Redirect, Template> {
let user = get_user(&login_form.username).unwrap();
match user {
Some(existing_user) => if verify(&login_form.password, &existing_user.password_hash).unwrap() {
return Ok(Redirect::to(uri!(home)))
},
// we now hash (without verifying) just to ensure that the timing is the same
None => {
hash(&login_form.password, DEFAULT_COST);
},
};
let mut response = Template::render("login", &LoginContext {
error: Some(String::from("Invalid username or password!")),
});
// TODO: <<<<<<<<<< HOW CAN I SET AN HTTP STATUS CODE TO THE RESPONSE?
Err(response)
}
我正在尝试设置 HTTP 状态响应代码,但我找不到正确的方法来执行此操作?最好用 200 以外的其他内容通知浏览器登录不成功。
最佳答案
来自Template docs (特别是 Responder 特征):
Returns a response with the Content-Type derived from the template's extension and a fixed-size body containing the rendered template. If rendering fails, an
Err
ofStatus::InternalServerError
is returned.
尝试制作一个新的 Error
派生 Responder 特征的枚举。而不是返回 Result<Redirect, Template>
, 返回 Result<Redirect, Error>
其中 Error
看起来像这样:
#[derive(Debug, Responder)]
enum Error {
#[response(status = 400)]
BadRequest(Template),
#[response(status = 404)]
NotFound(Template),
}
关于rust - 如何设置 (Rust) Rocket API 端点模板响应的 HTTP 状态代码?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/60908423/