1.csv
cut price depth carat table
0 Good 327 57.9 0.23 65.0
1 Good 335 63.3 0.31 58.0
2 Very Good 336 62.8 0.24 57.0
3 Very Good 336 62.3 0.24 57.0
4 Very Good 337 61.9 0.26 55.0
5 Premium 326 59.8 0.21 61.0
6 Premium 334 62.4 0.29 58.0
7 Good 400 64.0 0.30 55.0
2.csv
cut price depth carat table
0 Good 327 57.9 0.23 65.0
1 Good 335 63.3 0.31 58.0
2 Very Good 336 62.8 0.24 57.0
3 Very Good 336 62.3 0.24 57.0
4 Very Good 337 61.9 0.26 50.0
5 Premium 326 59.8 0.21 61.0
6 Premium 334 60.4 0.29 58.0
7 Good 399 64.0 0.30 55.0
2.csv 仅更改了 4,6,7 行
我正在寻找
输出如下
cut price depth carat table
4 Very Good 337 61.9 0.26 50.0
6 Premium 334 60.4 0.29 58.0
7 Good 399 64.0 0.30 55.0
任何人都可以分享您的经验吗?任何形式的帮助都可以
import pandas as pd
f1 = pd.read_csv('1.csv')
f2 = pd.read_csv('2.csv')
columns_list = ['cut', 'price', 'depth', 'carat', 'table']
new_df= f2[~f2.price.isin(f1.price)]
print(new_df)
这是我编写的示例代码,它工作正常,但我需要使用
f2[~f2.price.isin(f1.price)]
在循环中获取“价格”空间上的每个列名称,并且还将返回值。我尝试像这样的正常方式
for i in columns_list:
price = f2[~f2.i.isin(f1.i)]
print(price)
但是 pandas 命令不能像这样工作,它会返回类似的错误
AttributeError: 'DataFrame' object has no attribute 'i'
感谢您的阅读,希望您能理解
最佳答案
IIUC,DataFrame.merge
与指示器= True
:
f2_filtered = (f2.merge(f1, how='outer', indicator=True)
.query('_merge == "left_only"')
.drop(columns = '_merge'))
print(f2_filtered)
输出
cut price depth carat table
4 Very_Good 337 61.9 0.26 50.0
6 Premium 334 60.4 0.29 58.0
7 Good 399 64.0 0.30 55.0
关于python - for 循环中的 pandas isin 函数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/60975485/