我正在尝试删除数组/json 中不包含字符串中所有单词的所有元素。例如:
要查找的单词:世界坚持
Array [
{
"title" : "Hold On World",
"artist": "some guy"
},
{
"title" : "World, Hold On",
"artist": "some guy"
},
{
"title" : "World Hold On Now",
"artist": "some guy"
},
{
"title" : "World Is Ending",
"artist": "some guy"
}
]
因此,对于这个数组,应该保存前三个元素,但应该删除最后一个元素,我尝试过这样的操作:
def removeNonMatches(data, title):
old = title.split(' ')
new = '|'.join(old)
p = re.compile(new, re.I)
for x in data:
if bool(p.search(r"\b("+p+")\b", x['title'], re.IGNORECASE)) == False:
data.remove(x)
return data
data = [
{
"title" : "Hold On World",
"artist": "some guy"
},
{
"title" : "World, Hold On",
"artist": "some guy"
},
{
"title" : "World Hold On Now",
"artist": "some guy"
},
{
"title" : "World Is Ending",
"artist": "some guy"
}
]
title = 'World Hold On'
new_data = removeNonMatches(data, title)
最佳答案
您可以使用
data = [
{
"title" : "Hold On World",
"artist": "some guy"
},
{
"title" : "World, Hold On",
"artist": "some guy"
},
{
"title" : "World Hold On Now",
"artist": "some guy"
},
{
"title" : "World Is Ending",
"artist": "some guy"
}
]
words = ["World", "Hold", "On"]
keep = [item for item in data
if all(word in item["title"] for word in words)]
print(keep)
哪个产量
[{'title': 'Hold On World', 'artist': 'some guy'},
{'title': 'World, Hold On', 'artist': 'some guy'},
{'title': 'World Hold On Now', 'artist': 'some guy'}]
如果想要包含大写和小写单词,请使用
words = ["world", "hold", "on"]
keep = [item for item in data
if all(word in item["title"].lower() for word in words)]
关于python - 从数组的元素中查找所有匹配的单词,保留这些单词,但删除不包含这些单词的元素,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/61693263/