python - 如何以嵌套字典格式对值进行排序？

Question

我目前有一个字典，其键为:string，值是另一个dict。

如何按内部字典中的值排序？(我想按数字、14、8、2 等排序)

示例字典数据:

{
    "00": {
        "057fa729df76467eac31febae7c3d0587ab1db327eb4c9532ebbd63b3273df4d.json": 14,
        "067d2aaa8a300407c4b54f67c1fbb6c96aa3fe5ac8b71877e32636e5c0c5efe8.json": 2,
        "0d18dc8d9bf832afd01788bae9922d66a77acd7aa2ac07a1b292cb59c440345e.json": 8,

    },
    "000": {
        "02793d53bc9ed92d33207b0bbd03a63fffdf091ba98b2a1607242551ec850c88.json": 1,
        "02a606bed4864c58a78b1f1f60a7a8e6f297975c35ac889aaf717b205918cf57.json": 1,
        "03a735ca0ba08089106f1601ca391c34cdfbe0ec9b266fd66cc46f37c8f554de.json": 2,
    }
}

---

预期输出:

按数字排序后，它会从最大数字到最小数字打印(格式不必是这样，但你明白了):

    "057fa729df76467eac31febae7c3d0587ab1db327eb4c9532ebbd63b3273df4d.json": 14,
    "0d18dc8d9bf832afd01788bae9922d66a77acd7aa2ac07a1b292cb59c440345e.json": 8,
    "067d2aaa8a300407c4b54f67c1fbb6c96aa3fe5ac8b71877e32636e5c0c5efe8.json": 2,

---

我的尝试:

当键匹配“00”时，它将打印出该键:值对中的所有值。

for key, value in data.items()
    for k, v in sorted(value.items(), lambda x: x[1]):
        if key == "00":
           print(key)

Answer 1

像这样:

In [298]: my_dict = {}

In [299]: for key,value in data.items(): 
     ...:     my_dict[key] = {k: v for k, v in sorted(value.items(), key=lambda item: item[1], reverse=True)} 
     ...:                                                                                                                                                                                                   

In [300]: my_dict                                                                                                                                                                                           
Out[300]: 
{'00': {'057fa729df76467eac31febae7c3d0587ab1db327eb4c9532ebbd63b3273df4d.json': 14,
  '0d18dc8d9bf832afd01788bae9922d66a77acd7aa2ac07a1b292cb59c440345e.json': 8,
  '067d2aaa8a300407c4b54f67c1fbb6c96aa3fe5ac8b71877e32636e5c0c5efe8.json': 2},
 '000': {'03a735ca0ba08089106f1601ca391c34cdfbe0ec9b266fd66cc46f37c8f554de.json': 2,
  '02793d53bc9ed92d33207b0bbd03a63fffdf091ba98b2a1607242551ec850c88.json': 1,
  '02a606bed4864c58a78b1f1f60a7a8e6f297975c35ac889aaf717b205918cf57.json': 1}}

或者，您可以使用嵌套字典理解:

In [305]: {key: {k: v for k, v in sorted(value.items(), key=lambda item: item[1], reverse=True)} for key,value in data.items()}                                                                             
Out[305]: 
{'00': {'057fa729df76467eac31febae7c3d0587ab1db327eb4c9532ebbd63b3273df4d.json': 14,
  '0d18dc8d9bf832afd01788bae9922d66a77acd7aa2ac07a1b292cb59c440345e.json': 8,
  '067d2aaa8a300407c4b54f67c1fbb6c96aa3fe5ac8b71877e32636e5c0c5efe8.json': 2},
 '000': {'03a735ca0ba08089106f1601ca391c34cdfbe0ec9b266fd66cc46f37c8f554de.json': 2,
  '02793d53bc9ed92d33207b0bbd03a63fffdf091ba98b2a1607242551ec850c88.json': 1,
  '02a606bed4864c58a78b1f1f60a7a8e6f297975c35ac889aaf717b205918cf57.json': 1}}