python - 如何关联两个列表？

Question

我有两个列表和一些参数。在这些输入的帮助下，我可以对电池进行充电和放电。第一个列表中有 0 和 1。 0 表示对电池放电，1 表示对电池充电。在第二个列表中，有一些值，在它们的帮助下我们可以为电池充电。 电池参数为:

Max_capacity = 600MW
initial_capacity = 0MW
Duration = 4hours
battery size = 150MW

两个列表中实际上都有 8760 个值，但我只显示了几个

signal = [1,1,1,1,0,0,0,0,0,1,1,1,0,0]
excess_energy = [0,100,90,160,20,0,0,0,0,0,50,60,70,0]

所以这里有几个条件:

1. 只有当信号为1并且excess_energy大于0时电池才能充电。
2. 如果 extra_energy 大于 150MW，则电池将仅以 150MW 充电，如果小于，则可以以任何多余能量值充电。
3. 电池只有在信号为0时才能放电，固定时间150MW。

4. 电池不能放电到0以下，不能充电超过600MW 预期输出:

   

我的方法:

battery_size = 150
duration = 4
initial_capacity = 0
max_capacity = 600
ans_charged = []
ans_discharged = []
discharge = 0
days_counter = 0
signal = [0, 0, 0, 0, 1, 1, 1, 1, 1, 0, 0, 0, 1, 1]  # Reversed the polarity
excess_energy = [0, 100, 90, 160, 20, 0, 0, 0, 0, 0, 50, 60, 70, 0]
for decider, ex_energy in zip(signal, excess_energy):
    days_counter += 1  # days counter because every new day all the counters are reset
    if decider == 1 and discharge < duration and max_capacity >= initial_capacity >=0:  # at 0 we charging and at 1 we are discharging
        initial_capacity -= battery_size
        if initial_capacity >= 0:
            ans_charged.append(initial_capacity)
            ans_discharged.append(0)
            discharge += 1
        else:
            ans_charged.append(0)
            ans_discharged.append(0)
            discharge += 1
    elif decider == 1:
        ans_charged.append(0)
        ans_discharged.append(0)
    elif decider == 0 and ex_energy > 0:
        if ex_energy < 150 and max_capacity >= initial_capacity >= 0:
            initial_capacity += ex_energy
            if initial_capacity <= max_capacity:
                ans_discharged.append(initial_capacity)
                ans_charged.append(0)
            else:
                ans_discharged.append(max_capacity)
                ans_charged.append(0)
        else:
            initial_capacity += 150
        if initial_capacity <= max_capacity:
            ans_discharged.append(initial_capacity)
            ans_charged.append(0)
        else:
            ans_discharged.append(max_capacity)
            ans_charged.append(0)
    elif decider == 0:
        ans_discharged.append(0)
        ans_charged.append(0)
        discharge = 0
    if days_counter == 24:
        days_counter = 0
        charge = 0
        discharge = 0
    print(ans_discharged)
    print(ans_charged)

我的输出:

Charge = [0, 100, 190, 340, 0, 0, 0, 0, 0, 0, 40, 100, 0, 0]
Discharge = [0, 0, 0, 0, 190, 40, 0, 0, 0, 0, 0, 0, 0, 0]

我知道这是一个大问题，但有人可以帮忙回答吗，因为正如你所看到的，我得到了 40 和 100，而不是 50 和 110

Answer 1

您的代码非常复杂，可以简化:

signal = [1,1,1,1,0,0,0,0,0,1,1,1,0,0]
excess_energy = [0,100,90,160,20,0,0,0,0,0,50,60,70,0]
charge = []
discharge = []

current = 0
for i, value in enumerate(signal):
    if value == 0 : # Discharging
        current = max(current - 150, 0)
        discharge.append(current)
        charge.append(0)
    else:
        current = current + min(excess_energy[i], 150)
        charge.append(current)
        discharge.append(0)

print(charge)
print(discharge)