python-3.x - 用 % 按数字拆分 pandas 列

Question

我有一个 df，其中一列如下所示:

**Share**
We are safe 25%
We are always safe 12.50% (India Aus, West)
We are ok (USA, EU)
We are not OK
What is this
Always wise 25.66%

我想拆分此列，以便将适用的 % 值从该列拆分为新的值。 所以输出将是

Share                  Percent    LOCATION
We are safe            25%  
We are always safe     12.50%     India Aus, West
We are ok                         USA, EU
We are not OK
What is this
Always wise            25.66%

我认为下面会将其从右侧拆分，但它不起作用

df['Percent'] = df['Share'].str.rsplit(r' \d',1).str[0]

Answer 1

您可以提取这些值:

df[['Share','Percent']] = df['Share'].str.split(r'\s+(?=\d+(?:\.\d+)?%\s*$)',expand=True).fillna("")

Pandas 测试:

import pandas as pd
df = pd.DataFrame({'Share':['We are safe 25%','We are ok', 'We are always safe 12.50%']})
df[['Share','Percent']] = df['Share'].str.split(r'\s+(?=\d+(?:\.\d+)?%\s*$)',expand=True).fillna("")
>>> df
                Share Percent
0         We are safe     25%
1           We are ok        
2  We are always safe  12.50%

请参阅regex demo 。详情:

• \s+ - 一个或多个空格
• (?=\d+(?:\.\d+)?%\s*$) - 与紧随其后的位置匹配的正向前瞻:
  • \d+ - 一位或多位数字
  • (?:\.\d+)? - 可选的 . 序列和一个或多个数字
  • % - % 符号
  • \s* - 0 个或多个尾随(接下来是 $)空格和
  • $ - 字符串结尾。