TL;DR如下
我正在尝试使用多核处理包编写一些 C++ 代码。该包有一个很好的发送者类,我用它在线程之间发送消息。它看起来像这样:
// structs provided by the package
struct GlobalVarsContainer {
// some global vars
};
template<typename ...Ts>
struct sender {
GlobalVarsContainer* my_container;
sender (GlobalVarsContainer& c) : my_container(&c);
void send(Ts... args) {
// send the messages of types Ts
};
};
这个类的构造函数实际上有点复杂,所以我希望只调用一次构造函数。 我决定对我需要的所有发件人使用容器类型,所以像这样:
typedef std::tuple<
sender<uint32_t,uint32_t>,
sender<uint32_t,double>,
sender<uint32_t,double>
> sender_container_1_t;
typedef std::tuple<
sender<uint32_t,double>,
sender<uint32_t,double>,
sender<uint32_t,double>
> sender_container_2_t;
现在我可以构造一个 sender_container_1_t
并通过引用我的所有函数来传递它,万岁!
但这很丑陋,你必须像这样实例化容器:
GlobalVarsContainer gvc1, gvc2;
sender_container_1_t c1(gvc1, gvc1, gvc1);
sender_container_2_t c2(gvc2, gvc2, gvc2);
我想要某种形式的东西
GlobalVarsContainer gvc1, gvc2;
// Should have a tuple of senders of type sender<uint32_t,uint32_t>, sender<uint32_t,double> and sender<uint32_t,double>, all constructed with a reference to gvc as an argument.
sender_container<uint32_t,double,double> c1(gvc1);
// Should have a tuple of senders of type sender<uint32_t,double>, sender<uint32_t, double> and sender<uint32_t, double>, all constructed with a reference to gvc as an argument.
sender_container<double,double,double> c2(gvc2);
所以我想到使用可变参数容器结构,如下所示:
// My sender container
template<typename... Ts>
struct SenderContainer {
std::tuple<sender<uint32_t, Ts>...> my_senders;
// What to do for the constructor ?
};
但我不知道该怎么做才能做到SenderContainer<uint32_t,double,double> my_container(gvc1)
这样gvc1
被转发到所有发送者的构造函数。有人有提示吗?
长话短说: 如果我有一个可变结构模板
template<typename ...Ts>
struct Bar {
Bar(Foo f){};
}
我可以制作一个以下形式的容器
template<typename ...Ts>
struct BarContainer{
std::tuple<Bar<int,Ts>...> bars
}
这样我就可以打电话BarContainer<int, double, long> newBarContainer(f)
和 Foo f
被转发到 BarContainer::bars
的所有构造函数.
最佳答案
您可以创建虚拟结构以允许您的pack expansion :
template <typename> struct tag{};
template<typename ...Ts>
struct Bar {
Bar(Foo f){};
};
template<typename ...Ts>
struct BarContainer{
BarContainer(Foo f) : bars{(tag<Ts>{}, f)...} {}
std::tuple<Bar<int,Ts>...> bars;
}
关于c++ - 将相同的参数转发给 C++ 中的可变元组构造函数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/65478164/