我在共享按钮中有执行此操作的代码:
NSString *aText = _textToOutput;
UIImage *aPhoto = [[UIImage alloc] initWithData: _photoData];
NSURL *website = [NSURL URLWithString:@"http://www.google.com/"];
NSArray *objectsToShare = @[aText, aPhoto, website];
/* NSArray *includeActivities = @[UIActivityTypeMessage,
UIActivityTypeMail,
UIActivityTypePostToFacebook,
UIActivityTypePostToTwitter,
UIActivityTypePostToFlickr]; */
UIActivityViewController *activityVC = [[UIActivityViewController alloc] initWithActivityItems:objectsToShare applicationActivities:nil];
NSArray *excludeActivities = @[UIActivityTypeAirDrop,
UIActivityTypeCopyToPasteboard,
UIActivityTypePrint,
UIActivityTypeAssignToContact,
UIActivityTypeSaveToCameraRoll,
UIActivityTypeAddToReadingList,
UIActivityTypePostToFlickr,
UIActivityTypePostToVimeo];
activityVC.excludedActivityTypes = excludeActivities;
[self presentViewController:activityVC animated:YES completion:nil];
}
但我可以发送短信和电子邮件,并且所有 3 个要共享的对象都会出现。但在 Twitter 上,该 URL 不会出现在弹出窗口中,而在 Facebook 上,弹出窗口中缺少 URL 和 NSString。 ios 或这些应用程序有什么变化吗?谢谢。
最佳答案
我正在使用以下代码在我的应用程序中共享。 也许对你有帮助。
代码是:
UIImage *screenshotTaken = @"Image Url";
NSString *message = @"My Application Name";
NSString *shareBody =@"put Link Here";
// NSLog(@"%@",shareBody);
NSArray *postItems = @[message,shareBody,screenshotTaken];
UIActivityViewController *activityVC = [[UIActivityViewController alloc]
initWithActivityItems:postItems
applicationActivities:nil];
[self presentViewController:activityVC animated:YES completion:nil];
此共享帖子在 iPhone 上默认设置。它在 Facebook、Twitter、Flickr 和电子邮件上共享。
关于ios - 通过 ios 8 事件 View Controller 在 Facebook 和 Twitter 上共享,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29892326/