我有一条 POST 消息,在给定的情况下我绝对必须在 Android 上发送,以至于我希望它继续尝试直到完成。我的理解是:
urlConnection.setConnectTimeout(0);
会继续尝试连接,直到连接成功,但实际发生的情况是 try block 失败,并且抛出了 UnknownHostException:
private class SendAlert extends AsyncTask<String, String, String> {
protected String doInBackground(String... strings) {
Log.d(TAG, "sendAlarm: sending alarm");
String stringUrl = createUri();
HttpsURLConnection urlConnection = null;
BufferedReader reader = null;
String postData = "";
Log.d(TAG, "sendAlarm: apikey: " + apiKey);
try{
Log.d(TAG, "sendAlarm: trying");
URL finalURL = new URL(stringUrl);
urlConnection = (HttpsURLConnection)finalURL.openConnection();
urlConnection.setReadTimeout(10000);
urlConnection.setConnectTimeout(0);
urlConnection.setRequestProperty("Content-Type", "application/json;charset=UTF-8");
urlConnection.setRequestProperty("Accept","application/json");
urlConnection.setRequestProperty("x-api-key",apiKey);
urlConnection.setRequestMethod("POST");
urlConnection.setDoInput(true);
urlConnection.setDoOutput(true);
int responseCode = urlConnection.getResponseCode();
Log.d(TAG, "doInBackground: response code = " + responseCode);
}catch (MalformedURLException e) {
e.printStackTrace();
Log.d(TAG, "doInBackground: error 1 " + e.toString());
}catch(UnknownHostException e){
Log.d(TAG, "doInBackground: e: " + e);
Log.d(TAG, "doInBackground: retrying");
}
catch(Exception e){
Log.d(TAG, "doInBackground: error 2 " + e.toString());
}
想知道在 Android 上设置帖子消息的最佳方法是什么,即使手机处于飞行模式 5 小时,也要不断尝试连接直到连接成功。
编辑:按照下面@user3252344的回答,直接在AyncTask的catch block 中再次调用该函数是否有任何问题:
catch(UnknownHostException e){
Log.d(TAG, "doInBackground: e: " + e);
Log.d(TAG, "doInBackground: retrying");
SendAlarm sendAlarm = new SendAlarm;
sendAlarm.execute();
}
最佳答案
将连接超时设置为0意味着不会超时,但如果连接失败,它仍然不会处理。我猜您会收到 UnknownHostException
,因为它无法访问 DNS 服务器,因此无法解析 url。
我建议您设置一个合理的连接超时,如果发生超时异常,则捕获并重新运行。
final int READ_TIMEOUT = 500; // Timeout
final int RETRY_MS = 2000; //Retry every 2 seconds
final Handler handler = new Handler();
Runnable myUrlCall = () -> {
try {
//Make things
urlConnect.setReadTimeout(READ_TIMEOUT);
//Make the URL call, do response
} catch (SocketTimeoutException e) {
handler.postDelayed(myUrlCall, RETRY_MS);
} catch (/* other unintended errors*/ e) {
//Log the error or alert the user
}
};
handler.post(myUrlCall);
可能更好的主意:在调用电话之前使用 Android 设置检查是否有互联网。如果没有互联网,请使用更长的延迟。 Something like this would be the code you're looking for .
关于Android 不断尝试 POST 直到成功,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/66665059/