我创建了以下函数,它接受一个数据框并输出多个图:
boxplot_depend_vs_independ <- function(df_train) {
train_int_names <- df_train %>% select_if(is.numeric)
int_names <- names(train_int_names)
for (i in int_names) {
assign(paste0("var_",i),
ggplot(train, aes_string(x = train$target, y = i)) +
geom_boxplot(color = 'steelblue', outlier.color = 'firebrick',
outlier.alpha = 0.35) +
labs(title = paste0(i,' vs target'), y = i, x= 'target') +
theme_minimal() +
theme(
plot.title = element_text(hjust = 0.45),
panel.grid.major.y = element_line(color = "grey",
linetype = "dashed"),
panel.grid.major.x = element_blank(),
panel.grid.minor.y = element_blank(),
panel.grid.minor.x = element_blank(),
axis.ticks.x = element_line(color = "grey")
)
)
}
myGlist <- list(var_YOJ) # Example of one grob in a list
gridExtra::grid.arrange(grobs = myGlist, nrow=4)
}
如何在创建图形对象时将其放入列表中,以便最终将它们传递给 grid.arrange 函数?分配函数将它们放入变量中,但如何让循环将其放入列表中?
最佳答案
而不是使用 assign
在全局环境中创建对象,初始化list
'myGlist' 在顶部,然后将每次迭代的输出分配给它
boxplot_depend_vs_independ <- function(df_train) {
train_int_names <- df_train %>%
select_if(is.numeric)
int_names <- names(train_int_names)
myGlist <- vector('list', length(int_names))
names(myGlist) <- int_names
for (i in int_names) {
myGlist[[i]] <-
ggplot(train, aes_string(x = train$target, y = i)) +
geom_boxplot(color = 'steelblue', outlier.color = 'firebrick',
outlier.alpha = 0.35) +
labs(title = paste0(i,' vs target'), y = i, x= 'target') +
theme_minimal() +
theme(
plot.title = element_text(hjust = 0.45),
panel.grid.major.y = element_line(color = "grey",
linetype = "dashed"),
panel.grid.major.x = element_blank(),
panel.grid.minor.y = element_blank(),
panel.grid.minor.x = element_blank(),
axis.ticks.x = element_line(color = "grey")
)
}
gridExtra::grid.arrange(grobs = myGlist, nrow=4)
}
关于r - 在R中使用分配函数时,如何将图形对象存储到列表中?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/67029782/