mongodb - Node mongoose 嵌入文档数组

Question

我这里有我的示例 userSchema:

{
    "_id": objectId("6092076ba811e50b565497ec"),
    "username": "<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="dbafbea8af9bbcb6bab2b7f5b8b4b6" rel="noreferrer noopener nofollow">[email protected]</a>",
    "address_book": [{
        "_id": objectId("6092b1120f7e370b954a2708"),
        "address": "address1",
        "address2": "address2",
    }, {
        "_id": objectId("6093edcb88796b0a5eba19a3"),
        "address": "test1",
       "address2": "test2",
    }]
}

我可以通过以下方式找到用户吗 objectId("6092076ba811e50b565497ec") 和 address_book._id object("6093edcb88796b0a5eba19a3")

它只返回我选择的address_book？我的预期返回数据应该是这样的

{
    "_id": objectId("6092076ba811e50b565497ec"),
    "username": "<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="166273656256717b777f7a3875797b" rel="noreferrer noopener nofollow">[email protected]</a>",
    "address_book": {
        "_id": objectId("6093edcb88796b0a5eba19a3"),
        "address": "test1",
       "address2": "test2",
    }
}

这是我的示例函数

let user = [];
await User.findOne({
   _id: id,
   "address_book._id": address_id,
 })
.then((result) => {
   console.log(result);
   user = result;
 })
 .catch((err) => console.log(err));
 return user;

有了这个我就得到了所有的地址簿

还有address_book._id有updateOrCreate函数吗？

提前谢谢您。

Answer 1

从 MongoDB 4.4 开始，您可以在 find 方法中使用聚合运算符，

• $filter 迭代 address_book 数组的循环并匹配 _id 条件
• $first 从上面过滤结果中选择第一个元素

await User.findOne({
  _id: id,
  "address_book._id": address_id
},
{
  username: 1,
  address_book: {
    $first: {
      $filter: {
        input: "$address_book",
        cond: { $eq: ["$$this._id", mongoose.Types.ObjectId(address_id)] }
      }
    }
  }
})

Playground