$wordsAry = explode(" ", $search);
$wordsCount = count($wordsAry);
$queryCondition = " WHERE ";
for($i=0;$i<$wordsCount;$i++) {
$queryCondition .= "`location` LIKE '%$wordsAry[$i]%'";
if($i!=$wordsCount-1) {
$queryCondition .= " OR ";
}
}
echo $queryCondition;
$sql1 = "SELECT * FROM `shelves_instruments`
:szukaj
ORDER BY location ASC";
$licz_ilosc = $connect_db -> prepare($sql1);
$licz_ilosc -> bindValue(':szukaj', $queryCondition, PDO::PARAM_STR);
$licz_ilosc -> execute();
$ilosc_stron = $licz_ilosc->rowCount();
WHERE
location
LIKE '%walida%'
Fatal error: Uncaught PDOException: SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near '' WHERE
location
LIKE '%walida%'' ORDER BY location ASC' at line 2 in
可能出了什么问题?
最佳答案
准备好的语句并不是替代文本的奇特方式。您无法将整个 WHERE
子句作为单个参数发送。
您需要创建一个如下所示的 WHERE
子句:
$where = "WHERE `location` like :term1 OR `location` like :term2";
然后创建您的条款,以便
$param1 = '%'.$firstTerm.'%' ;
$param2 = '%'.$secondTerm.'%' ;
然后将您的条款与您准备好的声明绑定(bind)
$query = "SELECT * FROM `shelves_instruments` ".$where." ORDER BY location ASC"
$licz_ilosc = $connect_db -> prepare($query);
$licz_ilosc->execute([
"term1"=>$param1,
"term2"=>$param2
]);
关于php - fatal error : Uncaught PDOException: SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in you,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/68968997/