sql - 如何在 SQL 中编写 where 子句来按一天中的时间过滤 DATETIME 列？

Question

我有带有 DATETIME 列时间戳的数据，我想将其过滤到 DATETIME 介于上午 9:30 到下午 5:30 之间的任意一天的记录集。最好的方法是什么？

更新:更改是因为我需要精确到分钟，而不仅仅是小时。对此感到抱歉。

Answer 1

您始终可以将其编写为用户定义函数，特别是如果您需要定期执行此操作

CREATE function  dbo.timepart (@date as SMALLDATETIME)
RETURNS SMALLDATETIME
AS
BEGIN
    RETURN @date - DATEADD(d, DATEDIFF(d,0,@date), 0)
END

然后像这样使用

SELECT * FROM table
WHERE dbo.timepart(date_field) BETWEEN '9:30' AND '17:30'

在 SQL Server 2005 中使用以下内容进行测试

DECLARE @dates TABLE (date DATETIME)

DECLARE @date DATETIME
SET @date = '20 MAR 2009'

WHILE @date < '22 MAR 2009'
    BEGIN
        INSERT INTO @dates VALUES(@date)
        SET @date = DATEADD(hour, 1, @date)
    END

SELECT * 
FROM
    @dates
WHERE
    dbo.timepart(date) BETWEEN '9:30' AND '17:30'

结果

date
-----------------------
2009-03-20 10:00:00.000
2009-03-20 11:00:00.000
2009-03-20 12:00:00.000
2009-03-20 13:00:00.000
2009-03-20 14:00:00.000
2009-03-20 15:00:00.000
2009-03-20 16:00:00.000
2009-03-20 17:00:00.000
2009-03-21 10:00:00.000
2009-03-21 11:00:00.000
2009-03-21 12:00:00.000
2009-03-21 13:00:00.000
2009-03-21 14:00:00.000
2009-03-21 15:00:00.000
2009-03-21 16:00:00.000
2009-03-21 17:00:00.000