我正在使用java。 我想根据 mousedrag 事件绘制矩形。如果用户拖动鼠标,则小程序上的矩形应根据当前鼠标坐标增大或减小。 我有以下代码。
在下面的代码中,我使用 [b]SelectionArea[/b] 类,它扩展了我正在其上执行绘图操作的 Canvas 。我在此类中使用 [b]image[/b] 变量进行双缓冲,以减少闪烁并保存小程序的先前状态(即小程序的绘制内容)
但是如果我绘制第一个矩形,代码就可以正常工作。如果我开始绘制第二个矩形,则先前绘制的矩形就会消失。我希望之前绘制的矩形出现在屏幕上
谁能告诉我如何解决这个问题
import java.awt.*;
import java.applet.Applet;
import java.awt.event.*;
/*
* This displays a framed area. When the user drags within
* the area, this program displays a rectangle extending from
* where the user first pressed the mouse button to the current
* cursor location.
*/
public class RectangleDemo extends Applet {
SelectionArea drawingPanel;
Label label;
public void init() {
GridBagLayout gridBag = new GridBagLayout();
GridBagConstraints c = new GridBagConstraints();
setLayout(gridBag);
drawingPanel = new SelectionArea(this);
c.fill = GridBagConstraints.BOTH;
c.weighty = 1.0;
c.gridwidth = GridBagConstraints.REMAINDER; //end row
gridBag.setConstraints(drawingPanel, c);
add(drawingPanel);
label = new Label("Drag within the framed area.");
c.fill = GridBagConstraints.HORIZONTAL;
c.weightx = 1.0;
c.weighty = 0.0;
gridBag.setConstraints(label, c);
add(label);
drawingPanel.setVisible(true);
validate();
}
public void paint(Graphics g){
drawingPanel.repaint();
}
public void update(Graphics g){
paint(g);
}
}
class SelectionArea extends Canvas implements ActionListener, MouseListener, MouseMotionListener{
Rectangle currentRect;
RectangleDemo controller;
//for double buffering
Image image;
Graphics offscreen;
public SelectionArea(RectangleDemo controller) {
super();
this.controller = controller;
addMouseListener(this);
addMouseMotionListener(this);
}
public void actionPerformed(ActionEvent ae){
repaintoffscreen();
}
public void repaintoffscreen(){
image = createImage(this.getWidth(), this.getHeight());
offscreen = image.getGraphics();
Dimension d = getSize();
if(currentRect != null){
Rectangle box = getDrawableRect(currentRect, d);
//Draw the box outline.
offscreen.drawRect(box.x, box.y, box.width - 1, box.height - 1);
//repaint();
}
}
public void mouseEntered(MouseEvent me) {}
public void mouseExited(MouseEvent me){ }
public void mouseClicked(MouseEvent me){}
public void mouseMoved(MouseEvent me){}
public void mousePressed(MouseEvent me) {
currentRect = new Rectangle(me.getX(), me.getY(), 0, 0);
repaintoffscreen();
}
public void mouseDragged(MouseEvent me) {
System.out.println("here in dragged()");
currentRect.setSize(me.getX() - currentRect.x, me.getY() - currentRect.y);
repaintoffscreen();
repaint();
}
public void mouseReleased(MouseEvent me) {
currentRect.setSize(me.getX() - currentRect.x, me.getY() - currentRect.y);
repaintoffscreen();
repaint();
}
public void update(Graphics g){
paint(g);
}
public void paint(Graphics g) {
g.drawImage(image, 0, 0, this);
}
Rectangle getDrawableRect(Rectangle originalRect, Dimension drawingArea) {
int x = originalRect.x;
int y = originalRect.y;
int width = originalRect.width;
int height = originalRect.height;
//Make sure rectangle width and height are positive.
if (width < 0) {
width = 0 - width;
x = x - width + 1;
if (x < 0) {
width += x;
x = 0;
}
}
if (height < 0) {
height = 0 - height;
y = y - height + 1;
if (y < 0) {
height += y;
y = 0;
}
}
//The rectangle shouldn't extend past the drawing area.
if ((x + width) > drawingArea.width) {
width = drawingArea.width - x;
}
if ((y + height) > drawingArea.height) {
height = drawingArea.height - y;
}
return new Rectangle(x, y, width, height);
}
}
此外,如果我在全屏模式下运行此代码,那么我会看到只有在释放鼠标后矩形才会出现在屏幕上。但我希望在拖动鼠标时矩形出现在屏幕上,并且它应该根据当前鼠标坐标更改其尺寸。 任何人都可以帮助我吗?
最佳答案
作业?
基本上你需要做的是:
- 鼠标按下时保持鼠标按下坐标并重新绘制
- 鼠标移动时保持当前鼠标坐标并重新绘制
- 鼠标松开时,使鼠标按下的坐标无效以指示没有矩形,然后重新绘制。
- 在绘画上,绘制背景,然后在鼠标按下和当前鼠标坐标之间进行调整。
如果你不想保留背景图像,你可以使用图形异或函数来实现一个技巧,绘制相同的矩形两次会删除旧的矩形,因此你可以使用它直接在屏幕上恢复旧图像图形对象。
编辑:代码异或用法示例:
public void paint(Graphics g)
{
g.setXORMode(Color.black);
// draw old rect if there is one. this will erase it
// draw new rect, this will draw xored
g.setDrawMode(); // restore normal draw mode
}
异或有一个有趣的属性:
xor(xor(x)) = x
因此,对同一像素进行两次异或可恢复其原始颜色。
关于java - 如何使用鼠标拖动事件在java小程序上绘制矩形,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/880753/