这些是示例数据:
CREATE OR REPLACE TYPE CourseList AS TABLE OF VARCHAR2(64);
CREATE TABLE department (
courses CourseList)
NESTED TABLE courses STORE AS courses_tab;
INSERT INTO department (courses)VALUES (CourseList('1','2','3'));
INSERT INTO department (courses)VALUES (CourseList('4','5','7'));
INSERT INTO department (courses)VALUES (CourseList('1','2'));
commit;
select d1.courses
from department d1
where not exists (select 1 from department d2
where d1.courses<> d2.courses and d1.courses submultiset of d2.courses);
commit;
Result:
CourseList(1,2,3)
CourseList(4,5,7)
该查询返回正确的数据 CourseList,它不是表的任何其他 CourseList 的子集。
关于如何在没有子查询的情况下做到这一点的一些想法,我认为可以使用同一个表的 join 来完成,但我不知道该怎么做。
谢谢。
最佳答案
我更喜欢你的子查询,我自己。但另一种选择是:
select d.courses
from department d
MINUS
select d2.courses
from department d2, department d1
where d1.courses<> d2.courses
and d1.courses submultiset of d2.courses;
关于sql - 在带有嵌套表列 sql oracle 的表中查找不相交的集合,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/9935578/