macos - Mac Bash 脚本在 Do 上失败?

标签 macos qt bash shell terminal

此脚本需要在 Mac OSX 上运行。下面的脚本是构建一个 QT QRC(资源文件定义),它只不过是一个具有不同扩展名的 XML 文件。我已经在 Mac 终端上测试了隔离的脚本的每个部分。一切都正常,但我无法让 for 循环正确执行。

这个脚本应该:

  1. 列出当前目录下的所有文件
  2. 去掉 find 产生的 ./
  3. 创建正确的 XML

结果应如下所示:

<RCC>
    <qresource prefix="/">
        <file>login.html</file>
        <file>start.html</file>
        <file>base/files.html</file>
    </qresource>
</RCC>

这是我当前的脚本:

 #!/bin/bash
    #Define the File
        file="Resources.qrc"
    #Clear out the old file, we want a fresh one
        rm $file
    #Format the start of the QRC file
        echo "<RCC>" >> $file
        echo "  <qresource prefix=\"/\">" >> $file
        #Iterate through the directory structure recursively
            for f in $(find . -type f)
                do
                    #Ensure the file isn't one we want to ignore
                        if [[ $f != "*.qrc" && $f != "*.rc" && $f != "*.h" && $f != "*.sh" ]]
                        then
                            #Strip out the ./ for the proper QRC reference
                                echo "<file>$f</file>" | sed "s/.\///" >> $file
                        fi
                done
    #Close the QRC file up
        echo "  </qresource>" >> $file
        echo "</RCC>" >> $file

这就是终端不断告诉我的内容:

'build-qrc.sh: line 11: syntax error near unexpected token `do
'build-qrc.sh: line 11: `           do

任何时候我尝试执行 shell for 循环时都会出现同样的错误。我尝试过分号之类的但无济于事。有任何想法吗?谢谢。


这是由 chepner 提供的最终脚本。它为 QT 生成完美的 QRC 资源文件,用于将 html 项目嵌入到 webkit 驱动的应用程序中。

#!/bin/bash
#Define the Resource File
file="AncestorSyncUIPlugin.qrc"
#Clear out the old file if it exists, we want a fresh one
if [ -f $file ] 
then
    rm $file
fi
# Use the -regex primary of find match files with the following
# extensions: qrc rc sh h. Use -not to negate that, so only files
# that don't match are returned. The -E flag is required for
# the regex to work properly. The list of files is stored in
# an array
target_files=( $(find -E . -type f -regex ".*\.(png|jpg|gif|css|html)$") )

# Use a compound statement to redirect the output from all the `echo`
# statements at once to the target file. No need to remove the old file,
# no need to append repeatedly.
{
    #Format the start of the QRC file
    echo "<RCC>"

    # Use single quotes to avoid the need to escape the " characters
    echo '  <qresource prefix="/">'

    # Iterate over the list of matched files
    for f in "${target_files[@]}"
    do
        # Use parameter expansion to strip "./" from the beginning
        # of each file
        echo "  <file>${f#./}</file>"
    done
    #Close the QRC file up
    echo "  </qresource>"
    echo "</RCC>"
} > $file

最佳答案

我没有看到任何语法错误,但 $f != "*.qrc" 不应按您的预期方式工作。它根据文字字符串 *.qrc 测试 f 的值。这是您的脚本,使用各种技巧进行了缩短:

#!/bin/bash
#Define the File
file="Resources.qrc"
# Use the -regex primary of find match files with the following
# extensions: qrc rc sh h. Use -not to negate that, so only files
# that don't match are returned. The -E flag is required for
# the regex to work properly. The list of files is stored in
# an array
target_files=( $(find -E . -type f -not -regex ".*\.(q?rc|s?h)$") )

# Use a compound statement to redirect the output from all the `echo`
# statements at once to the target file. No need to remove the old file,
# no need to append repeatedly.
{
    #Format the start of the QRC file
    echo "<RCC>"

    # Use single quotes to avoid the need to escape the " characters
    echo '  <qresource prefix="/">'

    # Iterate over the list of matched files
    for f in "${target_files[@]}"
    do
        # Use parameter expansion to strip "./" from the beginning
        # of each file
        echo "    <file>${f#./}</file>"
    done
    #Close the QRC file up
    echo "  </qresource>"
    echo "</RCC>"
} > $file

关于macos - Mac Bash 脚本在 Do 上失败?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/10728595/

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