asp.net-mvc - ASP.NET MVC ActionLink 保留 "old"路由参数

Question

我要过滤的两个链接:

@Html.ActionLink("Customer 1", "Index", new { customer = 1  })
@Html.ActionLink("Project A", "Index", new { project = "A"  })

我的带过滤器的 Controller :

public ViewResult Index(int? customer, int? project) {
        var query = ...

        if (customer != null) {
            query = query.Where(o => o.CustomerID == customer);
        }

        if (project != null) {
            query = query.Where(o => o.ProjectID == project);
        }
        return View(query.ToList());
}

我现在可以过滤客户或项目，但不能同时过滤两者!

如果我单击客户 1，url = Object?customer=1
如果我单击项目 A，url = Object?project=a
我希望能够先点击客户 1，然后点击项目 A 并获得 url = Object?customer=1&project=a
这是可能的还是我应该用另一种方式来做？

谢谢!

Answer 1

正确的方法是将带有各种参数的模型返回到您的 View 中。

型号

public class TestModel {
   public int? Customer { get; set; }
   public int? Project { get; set; }
   public List<YourType> QueryResults { get; set; }
}

查看

@model Your.Namespace.TestModel

...

@Html.ActionLink("Project A", "Index", new { customer = Model.Customer, project = Model.Project })

Controller

public ViewResult Index(TestModel model) {
    var query = ...

    if (model.Customer != null) {
        query = query.Where(o => o.CustomerID == model.Customer);
    }

    if (model.Project != null) {
        query = query.Where(o => o.ProjectID == model.Project);
    }

    model.QueryResults = query.ToList();

    return View(model);
}