string - MS SQL - 如何获取从大字符串中搜索的逗号/分号分隔的电子邮件地址列表

Question

如何提取字符串中所有可用电子邮件地址的列表(以逗号/分号分隔的列表形式)

SELECT dbo.getEmailAddresses('this is misc <a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="d2b3bcb6a0b7a592b5fcb1bdbf" rel="noreferrer noopener nofollow">[email protected]</a>')

--output <a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="a4c5cac0d6c1d3e4c38ac7cbc9" rel="noreferrer noopener nofollow">[email protected]</a>

SELECT dbo.getEmailAddresses('this is misc <a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="9bfaf5ffe9feecdbfcb5f8f4f6" rel="noreferrer noopener nofollow">[email protected]</a> and a medium text returning %<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="5a103532341a3b39373f74393537" rel="noreferrer noopener nofollow">[email protected]</a>')
--output <a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="d5b4bbb1a7b0a295b2fbb6bab8" rel="noreferrer noopener nofollow">[email protected]</a>; <a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="5f153037311f3e3c323a713c3032" rel="noreferrer noopener nofollow">[email protected]</a>

Answer 1

这是一个用于此目的的 UDF。如果您需要其他内容(例如电子邮件地址中的非英语符号)，请更正此行 SET @MailTempl='[A-Za-z0-9_.-]。 Here is a full list of allowed characters

CREATE FUNCTION [dbo].[getEmailAddresses] (@Str varchar(8000))  
RETURNS varchar(8000) AS  
BEGIN 

declare @i int, @StartPos int,@AtPos int,@EndPos int;
declare @MailList varchar(8000);
declare @MailTempl varchar(100);


SET @MailList=NULL;
SET @MailTempl='[A-Za-z0-9_.-]'; --allowing symbols in e-mail not including @

SET @AtPos=PATINDEX('%'+@MailTempl+'@'+@MailTempl+'%',@Str)+1;
While @AtPos>1
begin
  --go left
  SET @i=@AtPos-1;
  while (substring(@Str,@i,1) like @MailTempl) SET @i=@i-1;
  SET @StartPos=@i+1;

  --go right
  SET @i=@AtPos+1;
  while (substring(@Str,@i,1) like @MailTempl) SET @i=@i+1;
  SET @EndPos=@i-1;

  SET @MailList=isnull(@MailList+';','')+Substring(@Str,@StartPos,@EndPos-@StartPos+1);

  --prepare for the next round
  SET @Str=substring(@Str,@EndPos+1,LEn(@Str));
  SET @AtPos=PATINDEX('%'+@MailTempl+'@'+@MailTempl+'%',@Str)+1;

end;

RETURN @MailList;

END