ios - NSString 去掉括号

Question

我正在使用此函数删除括号及其内部:

+(NSString*)removeCharsBetweenBrackets:(NSString*)str {
NSRange range = [str rangeOfString:@"("];
if (range.location != NSNotFound) {
    NSRange range2 = [str rangeOfString:@")"];

    if (range2.location != NSNotFound) {
        NSString *str1 = [str substringToIndex:range.location];
        NSString *str2 = [str substringFromIndex:range2.location + 1];
        str = [NSString stringWithFormat:@"%@ %@",str1,str2];
    }
}

range = [str rangeOfString:@"["];
if (range.location != NSNotFound) {
    NSRange range2 = [str rangeOfString:@"]"];

    if (range2.location != NSNotFound) {
        NSString *str1 = [str substringToIndex:range.location];
        NSString *str2 = [str substringFromIndex:range2.location + 1];
        str = [NSString stringWithFormat:@"%@ %@",str1,str2];
    }
}

return str;
}

我调用了两次删除了两次，它完美地删除了它。

问题是当我有这样的字符串时:

Mystring(blablabla)(*).mp3

* - Is a number. can be 0-999

我只想删除 (*)。

我如何实现它？

编辑:

字符串可以是:

mystring(bla bla)(1).mp3
mystring(bla bla)(1123).mp3
mystring(99).mp3
mystring(9).mp3
mystring.mp3
mystring(bla bla).mp3

如果 (number) 存在，我需要删除它。

Answer 1

NSRegularExpression *regexp = [NSRegularExpression regularExpressionWithPattern:@"\\([0-9]{1,3}\\)" options:0 error:NULL];

NSString *result = [regexp stringByReplacingMatchesInString:string
                                                    options:0
                                                      range:NSMakeRange(0, [string length])
                                               withTemplate:@""];