我正在尝试在 phpseclib 中使用 RSA 实现,我认为在函数中执行一次代码并重新使用该函数会更容易。 当我尝试向代码发送短信时,我收到一条错误消息,提示“解密错误” 测试还让我意识到每次代码运行时密文都是不同的,所以我显然在那里做错了什么!
函数的代码是:
require_once "Crypt/RSA.php";
require_once "Crypt/AES.php";
//Function for encrypting with RSA
function rsa_encrypt($string, $public_key)
{
//Create an instance of the RSA cypher and load the key into it
$cipher = new Crypt_RSA();
$cipher->loadKey($public_key);
//Set the encryption mode
$cipher->setEncryptionMode(CRYPT_RSA_ENCRYPTION_PKCS1);
//Return the encrypted version
return base64_encode($cipher->encrypt($string));
}
//Function for decrypting with RSA
function rsa_decrypt($string, $private_key)
{
//Create an instance of the RSA cypher and load the key into it
$cipher = new Crypt_RSA();
$cipher->loadKey($private_key);
//Set the encryption mode
$cipher->setEncryptionMode(CRYPT_RSA_ENCRYPTION_PKCS1);
//Return the decrypted version
return $cipher->decrypt($string);
}
我尝试使用以下方法对其进行测试: ( key 仅用于测试,这就是其硬编码的原因)。 正是在这里,每次运行代码时, $ciphertext 的值都会改变
//Private key
$private_key = "-----BEGIN RSA PRIVATE KEY----- MIICXAIBAAKBgQCU+1bLfPmcY7qrF/dTbAtuJlv4R/FVc1WEH9HKU0jQjX/n/db9vz/x0i3te/bK LNEcwUhBu+PWPnOt/qVURG9BUT6RsCRFUn0CyGiUKoy45o9K/mJAHmbrNtrUB6ckrYLF75Y50nUN sBVHUDw8yQymmiOBT1gc/KM5s1xTz44LMwIDAQABAoGAGsiMtAyFu23ac0PdvOuhqm3O/vXAF0Ki zxwBVURfxM6LfiOOcRPe5RSKGTW+Cl7AQVEmMlsa/LtBhLhQ9LNQ5L/4oTmRhCGiZZEmccAdjKsx yMeaxkp+ZHvMxMKQNDgYg1CXqrCrpwwUuMUlA26tfxZ3xSFtFyDTaV9mgDQ1IGECQQCkX9Tum7D1 vQTwbhbYnu7eC4eUOaZeGWSEs2csK7U6vfZ3BzUZW/0tPqcSpQqcNxMtY9TiUsNRj1uM6jX3byp7 AkEA6Ab+wvOTNRtES77OAYG9gHGZZ+iXjQJ/6Z7JehN4p41UbDIf9nNUOLUPL9z5V1uOYnl1CWoo Cw95cdhKXxEAqQJBAIU5Or6tp250ZdVslM27ewSyuY9UblfkIsk/EscFIdzbbDAqwkmsefW6yvTc mU3lgYCPYlKRG8c19tCuX1ENY5MCQAz37x9YW975Ai01ofAFn2DheJCNOINCI4IcROiU1AaRaKmP d6fftFJjFFE5iZovXNr2LOt0yn4rxD7vtuBvY9kCQGyty6YCB6qaD7qXPMhLrLbGajAIWd6ETgxv frK/BJu+buPfDky/g1FhI5R9iMtL1xH0JYLJlaVocU+xSeA9DkY= -----END RSA PRIVATE KEY-----";
//Public key
$public_key = "-----BEGIN PUBLIC KEY----- MIGfMA0GCSqGSIb3DQEBAQUAA4GNADCBiQKBgQCU+1bLfPmcY7qrF/dTbAtuJlv4R/FVc1WEH9HK U0jQjX/n/db9vz/x0i3te/bKLNEcwUhBu+PWPnOt/qVURG9BUT6RsCRFUn0CyGiUKoy45o9K/mJA HmbrNtrUB6ckrYLF75Y50nUNsBVHUDw8yQymmiOBT1gc/KM5s1xTz44LMwIDAQAB -----END PUBLIC KEY-----";
//Test out the rsa encryption functions
$plaintext = "This is some plaintext to encrypt";
$ciphertext = rsa_encrypt($plaintext, $public_key);
$decipheredtext = rsa_decrypt($ciphertext, $private_key);
//Echo out results
echo sprintf("<h4>Plaintext for RSA encryption:</h4><p>%s</p><h4>After encryption:</h4><p>%s</p><h4>After decryption:</h4><p>%s</p>", $plaintext, $ciphertext, $decipheredtext);
编辑: 示例输出为:
RSA 加密的明文:
这是我们将加密的一些明文
加密后:
'~!ˆ_æžWýF�E×9&ùš!´jéÓb÷á劀É7J+Ûªß̄׎Èã©¡É£#(÷)�X„)÷O'˱N@Øv«ÓÌPf¹—â!a ���a&Á�����ö�ŠCðJ«vW{uAåoO�XäÞ#÷ï`agÏ:OŒ
解密后:
//什么也没返回,这里是空白
最佳答案
我认为 GigaWatt 的答案是正确的。至于这个:
Testing also made me realise that the ciphertext was different every time the code ran, so I'm clearly doing something wrong there!
PKCS#1 填充添加随机字节,因此密文始终不同。然而,PKCS#1 算法知道明文何时结束以及随机字节何时开始,因此它能够将两者分开并返回您想要的结果。
编辑:在用新行替换键中的空格后,我让它开始工作。例如。
$private_key = "-----BEGIN RSA PRIVATE KEY-----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-----END RSA PRIVATE KEY-----";
//Public key
$public_key = "-----BEGIN PUBLIC KEY-----
MIGfMA0GCSqGSIb3DQEBAQUAA4GNADCBiQKBgQCU+1bLfPmcY7qrF/dTbAtuJlv4R/FVc1WEH9HK
U0jQjX/n/db9vz/x0i3te/bKLNEcwUhBu+PWPnOt/qVURG9BUT6RsCRFUn0CyGiUKoy45o9K/mJA
HmbrNtrUB6ckrYLF75Y50nUNsBVHUDw8yQymmiOBT1gc/KM5s1xTz44LMwIDAQAB
-----END PUBLIC KEY-----";
关于php - 在 PHP 中使用 phpseclib 时出现 RSA 问题,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/15750587/