arrays - Bash shell 数组操作

Question

我有一个小脚本，它从文本文件中读取行并将它们存储在数组中。

#!/bin/bash

while read line 
do
    array+=("$line")
done < $1

for ((i=0; i < ${#array[*]}; i++))
do
    echo "${array[i]}"
done

这是我的文本文件中的行，在运行脚本后打印:

This is line1 of file1 with 10 words.
This is line2 of file2 with 100 words.
This is line3 of file3 with 1000 words.
...

到目前为止一切都很好。从这里开始，我尝试使用单词并形成一个新的语句集。最终输出将按以下格式构建:

Capture ThisFile info-count1
filenum file1
Position of line: line1; Count of words: 10

有没有办法可以迭代每个数组元素(行字)并执行此操作？

基本上，从这里开始，当我在数组中包含行时，我想迭代每一行，选取该行中的某些单词并创建一个新的语句集。

...... 更新: ......

这就是我最终做到的:

#!/bin/bash

while read line
do
    getthelines=($line)
    printf '\n'
    echo "Capture ThisFile info_count"
    echo "filenum ${getthelines[4]}"
    echo "Position of line: ${getthelines[2]}; Count of words: ${getthelines[6]}"
    printf '\n'
done < $1

非常感谢。

See also:

• Split string into an array in Bash
• Redirect output to a bash array
• How to iterate over associative arrays in Bash
• Iterate over bash arrays, substitute array name dynamically, is this possible?

Answer 1

没办法。我昨天编写了这段代码来迭代数组。

line="This is line1 of file1 with 10 words."
words=($line)
for word in ${words[@]};
do 
    echo "Word: $word"
done

输出:

Word: This
Word: is
Word: line1
Word: of
Word: file1
Word: with
Word: 10
Word: words.