sql - Oracle PL SQL Procedure 需要修改以接受具有所有类型字符的数组并拆分

Question

我有一个 PUSH_DATA 过程，它接受以下格式的输入数据:

["value 1","value 2","value 3","value n"]

(所有细节都可以在最后的 db fiddle 链接中找到)

然后它将逗号分隔值拆分为目标表的数据库列。

现在，问题是输入字符串由最终用户传递，他有时会在两者之间引入多个双引号，主要拆分标准基于双引号。

该过程以 fiddle 形式出现在此处，最后传递了一个字符串示例来演示该问题。

所以当过程被传递为:

BEGIN
PUSH_DATA(110,'["Project title afor BYU heads","The values are,\n "exactly" up to the requirement and analysis done by the team.
Also it is difficult to,\n prepare a scenario notwithstanding the fact it is difficult. This user story is going to be slightly complex however it is up to the team","Active","Disabled","25 tonnes of fuel","www.examplesites.com/html.asp&net;","Apprehension","","","","25","Stable"]');
END;
/

结果符合预期:

当字符串传递时带有额外的引号如下:

BEGIN
PUSH_DATA(110,'[""Project title afor BYU heads"","The values are,\n "exactly" up to the requirement and analysis done by the team.
Also it is difficult to,\n prepare a scenario notwithstanding the fact it is difficult. This user story is going to be slightly complex however it is up to the team","Active","Disabled","25 tonnes of fuel","www.examplesites.com/html.asp&net;","Apprehension","","","","25","Stable"]');
END;
/

由于额外的引号，结果出乎意料:

要求是忽略引号内的任何特殊字符，因为它应该显示而不是被评估而忽略，例如额外的双引号或/或\将被忽略并按原样传递字符串。

所以如果传递一个值，"Hi There""s, No" 输出应为 Hi there""s, No .

因此，我需要修改解决方案，这样

1. 使用现有的正则表达式条件并添加条件以在双引号内包含双引号
2. 或者，不是将参数作为 varchar 传递，而是使用数组或适合该场景的任何其他解决方案。

摆弄所有细节:

Answer 1

(select data_string from dual),
    rcte (id, data, lvl, result)
    AS (
         SELECT p_id, data, 1,regexp_substr(data,
                '(".*?")(,|\])', 1, 1, 'n', 1) result
           FROM (select data_string data from input) 
        UNION ALL
         SELECT id, data, lvl + 1,
                regexp_substr(data, '(".*?")(,|\])', 1, lvl + 1, 'n', 1)
           FROM rcte
        WHERE lvl <= regexp_count(data, '(".*?")(,|\])',1,'n')
       )

• 从第一个选择查询中删除了 regex_replace，而不是直接使用数据。

• regexp_substr(data,'(".*?")(,|\])', 1, 1, 'n', 1) null 被替换为 'n' 以便在我们在正则表达式中使用点时匹配换行符。此正则表达式执行惰性匹配，直到找到 或 ] 字符。 ] 用于最后一个字符串。

• regexp_count(data, '(".*?")(,|\])',1,'n') 更改了正则表达式并替换了 null 与 'n' 匹配换行符。

https://dbfiddle.uk/?rdbms=oracle_18&fiddle=5826bffbab9937d497245487faa04c60