python - 检查命令是否有检查 "guild_only"

Question

我正在尝试为我的机器人制作一个 DM 帮助命令，该命令会根据我添加的命令数量自动生成。我希望它省略带有 guild_only 检查的命令。

这是我的代码:

import discord
from discord.ext import commands
...
...

# Imagine that in this case, `command` is a command with the `guild_only` check.
# This is in a much larger for loop
if commands.guild_only not in command.checks:
    # add command to string of commands
    help_c = ''.join([help_c, f"`{ctx.prefix}{command.name}{brief}`"
                              f"{separate_into_aliases(command)}\n{desc}\n\n"])

我假设 commands.guild_only not in command.checks 会返回 False，因为 guild_only 检查是 在检查列表中。但它没有。

这是 guild_only 返回的命令的检查属性列表:

[<function guild_only.<locals>.predicate at 0x04A60150>]

这里是 commands.guild_only:

<function guild_only at 0x0481F150>

两者相似但不相同。

我的问题是如何检查命令是否在其 checks 属性中具有 guild_only 检查？

Answer 1

你可以做类似的事情

@commands.guild_only()
@commands.is_owner()
@commands.command()
async def show_checks(self, ctx):
    checks = list(map(lambda s: s.split('.')[0], map(lambda f: f.__qualname__, ctx.command.checks)))
    # printing checks gives ['is_owner', 'guild_only']
    checks = [s.split('.')[0] for s in [f.__qualname__ for f in ctx.command.checks]]
    # same result but shorter code