我读了这篇文章 Draw dotted (not dashed!) line, with IBDesignable in 2017关于绘制虚线(而不是虚线)。但是,我一般不太熟悉图形,我想知道如何使用 CALayer 执行此操作(因此我不必执行整个获取当前图形上下文的操作)。
我正在尝试制作一条看起来像这样的虚线(白色部分,忽略背景):
这是我用来生成虚线的代码:
CAShapeLayer *shapelayer = [CAShapeLayer layer];
UIBezierPath *path = [UIBezierPath bezierPath];
[path moveToPoint:startPoint];
[path addLineToPoint:endPoint];
[path setLineCapStyle:kCGLineCapRound];
UIColor *fill = [UIColor whiteColor];
shapelayer.strokeStart = 0.0;
shapelayer.strokeColor = fill.CGColor;
shapelayer.lineWidth = 4.0;
shapelayer.lineJoin = kCALineJoinRound;
shapelayer.lineDashPattern = [NSArray arrayWithObjects:[NSNumber numberWithInt:4],[NSNumber numberWithInt:6 ], nil];
shapelayer.path = path.CGPath;
return shapelayer;
如何镜像我引用的 SO 帖子中的代码,但继续使用 CALayer?
我尝试像这样修改该帖子中的代码:
UIBezierPath * path = [[UIBezierPath alloc] init];
[path moveToPoint:startPoint];
[path addLineToPoint:endPoint];
[path setLineWidth:8.0];
CGFloat dashes[] = { path.lineWidth, path.lineWidth * 2 };
[path setLineDash:dashes count:2 phase:0];
[path setLineCapStyle:kCGLineCapRound];
[path stroke];
CAShapeLayer *returnLayer = [CAShapeLayer layer];
returnLayer.path = path.CGPath;
return returnLayer;
然而,这最终什么也没画。
最佳答案
希望对您有所帮助。
CAShapeLayer *circleLayer = [CAShapeLayer layer];
[circleLayer setPath:[[UIBezierPath bezierPathWithOvalInRect:CGRectMake(50, 50, 100, 100)] CGPath]];
circleLayer.lineWidth = 2.0;
[circleLayer setStrokeColor:[[UIColor redColor] CGColor]];
[circleLayer setFillColor:[[UIColor clearColor] CGColor]];
circleLayer.lineJoin = kCALineJoinRound;
circleLayer.lineDashPattern = [NSArray arrayWithObjects:[NSNumber numberWithInt:2],[NSNumber numberWithInt:3 ], nil];
// self.bgImage is parentView
[[self.bgImage layer] addSublayer:circleLayer];
self.bgImage.layer.borderWidth = 1.0f;
self.bgImage.layer.borderColor = [[UIColor blueColor]CGColor];
关于ios - 如何创建一个圆形虚线作为 CALayer?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37972424/