我有一个如下所示的文本文件:
garbage
moregarbaged89849843
MDeduri09ri44830
Some short sentence
Whatever ... key: d11001bfa937eee2f84f55a11b207356 (KID=01002d737832455680cffbadf1092baf)
Whatever2 ... key: a0ee2d0f8272355f750c5434db85291a (KID=0101bfa0ab9641a0b863ef76519a48d3)
Whatever3 ... key: fe216ba17e5af807ce5af8e43cf3c031 (KID=0102900a2bc54111833631ea7bb855ed)
77EB0A2C7C42EDC27A3D26E72A02BB29:01002d737832455680cffbadf1092baf status 'garbage'
blah blah:0101bfa0ab9641a0b863ef76519a48d3 has status 'usable'
77EB0A2C7C42EDC27A3D26E72A02BB29:blah blah
我只关心 key 和 KID 部分,想把它们提取到单独的列表中
我的正则表达式分别是 key: (\w|\d){30,}
和 KID=(\w|\d){30,}
.
我使用的代码是
matchkid = re.compile('KID=(\w|\d){30,}')
matchkey = re.compile('key: (\w|\d){30,}')
filteredkids = [a for a in lis if matchkid.search(a)]
filteredkeys = [b for b in lis if matchkey.search(b)]
print(filteredkids)
print('\n')
print(filteredkeys)
其中 lis
是由文本文档的行组成的列表
输出是
['Whatever ... key: d11001bfa937eee2f84f55a11b207356 (KID=01002d737832455680cffbadf1092baf)', 'Whatever2 ... key: a0ee2d0f8272355f750c5434db85291a (KID=0101bfa0ab9641a0b863ef76519a48d3)', 'Whatever3 ... key: fe216ba17e5af807ce5af8e43cf3c031 (KID=0102900a2bc54111833631ea7bb855ed)']
['Whatever ... key: d11001bfa937eee2f84f55a11b207356 (KID=01002d737832455680cffbadf1092baf)', 'Whatever2 ... key: a0ee2d0f8272355f750c5434db85291a (KID=0101bfa0ab9641a0b863ef76519a48d3)', 'Whatever3 ... key: fe216ba17e5af807ce5af8e43cf3c031 (KID=0102900a2bc54111833631ea7bb855ed)']
这是错误的,期望的输出是
['KID=01002d737832455680cffbadf1092baf', 'KID=0101bfa0ab9641a0b863ef76519a48d3', 'KID=0102900a2bc54111833631ea7bb855ed']
['key: d11001bfa937eee2f84f55a11b207356', 'key: a0ee2d0f8272355f750c5434db85291a', 'key: fe216ba17e5af807ce5af8e43cf3c031']
我尝试调整我的正则表达式并查看其他类似问题,但似乎没有任何效果,而且大多数时候我只是得到空列表。
希望能在这里找到一些指导,提前致谢
最佳答案
(\w|\d){30,}
不是一个好的模式,因为它创建了一个重复的捕获组,并且它本身是多余的:\w
匹配数字,所以 \w{30,}
就足够了。
接下来,您将使用仅返回 Match 数据对象的 re.search
,并使用 listeneing comprehension 迭代该对象,同时您需要从字符串中获取所有匹配项。
您可以通过使用修复代码
filteredkids = re.findall(r'KID=\w{30,}', text)
filteredkeys = re.findall(r'key: \w{30,}', text)
参见 Python demo :
import re
text = """garbage
moregarbaged89849843
MDeduri09ri44830
Some short sentence
Whatever ... key: d11001bfa937eee2f84f55a11b207356 (KID=01002d737832455680cffbadf1092baf)
Whatever2 ... key: a0ee2d0f8272355f750c5434db85291a (KID=0101bfa0ab9641a0b863ef76519a48d3)
Whatever3 ... key: fe216ba17e5af807ce5af8e43cf3c031 (KID=0102900a2bc54111833631ea7bb855ed)
77EB0A2C7C42EDC27A3D26E72A02BB29:01002d737832455680cffbadf1092baf status 'garbage'
blah blah:0101bfa0ab9641a0b863ef76519a48d3 has status 'usable'
77EB0A2C7C42EDC27A3D26E72A02BB29:blah blah"""
filteredkids = re.findall(r'KID=\w{30,}', text)
filteredkeys = re.findall(r'key: \w{30,}', text)
print( filteredkids )
print( filteredkeys )
输出:
['KID=01002d737832455680cffbadf1092baf', 'KID=0101bfa0ab9641a0b863ef76519a48d3', 'KID=0102900a2bc54111833631ea7bb855ed']
['key: d11001bfa937eee2f84f55a11b207356', 'key: a0ee2d0f8272355f750c5434db85291a', 'key: fe216ba17e5af807ce5af8e43cf3c031']
关于python - 将匹配的子字符串从列表中提取到 Python 中的新列表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/66970272/