linux-kernel - Linux 内核 - 错误 : Failed to allocate 0x6b3c bytes below 0x1000000

Question

我将我的 rootfs (CONFIG_INITRAMFS_SOURCE) 包含到我的内核中，所以内核现在有 17Mb 的大小:

$ ls -la uImage
-rw-r--r-- 1 kkr kkr 17669274 Dec  1 18:59 uImage
$ d2h 17669274
0x10D9C9A

由于它是压缩的，所以它会占用未压缩的 39Mb:

$ dd if=uImage of=uImage-x.gz bs=64 skip=1
$ file uImage-x.gz
uImage-x.gz: gzip compressed data, max compression, from Unix
$ gunzip uImage-x.gz
$ ls -la uImage-x 
-rw-r--r-- 1 kkr kkr 39852288 Dec  1 19:18 uImage-x
$ d2h 39852288
0x2601900

为什么我不能用这个命令通过 uBoot 启动我的内核？

=> setenv bootargs console=$consoledev,$baudrate $othbootargs

=> tftp 0x3000000 $bootfile
Speed: 100, half duplex
Using eTSEC1 device
TFTP from server 192.168.32.3; our IP address is 192.168.32.32
Filename 'uImage-powerpc'.
Load address: 0x3000000
Loading: #####################################################
done
Bytes transferred = 17669274 (10d9c9a hex)

=> tftp  0x2700000 $fdtfile;
Speed: 100, half duplex
Using eTSEC1 device
TFTP from server 192.168.32.3; our IP address is 192.168.32.32
Filename 'sat_92107.100.00C_p2020.dtb'.
Load address: 0x2700000
Loading: ##
done
Bytes transferred = 15164 (3b3c hex)

=> bootm 0x3000000 - 0x2700000
## Booting kernel from Legacy Image at 03000000 ...
   Image Name:   Linux-4.0.0-AOA00.01-00662-g07ae
   Created:      2015-12-01  17:59:21 UTC
   Image Type:   PowerPC Linux Kernel Image (gzip compressed)
   Data Size:    17669210 Bytes = 16.9 MiB
   Load Address: 00000000
   Entry Point:  00000000
   Verifying Checksum ... OK
## Flattened Device Tree blob at 02700000
   Booting using the fdt blob at 0x02700000
   Uncompressing Kernel Image ... OK
ERROR: Failed to allocate 0x6b3c bytes below 0x1000000.
device tree - allocation error

由于内核本身需要 0x10d9c9a 字节(压缩)或 0x2601900 字节(未压缩)，所以没有机会将设备树放在 0x1000000 下面.该值 (16Mb) 是否可配置？否则我提取的内核是否小于 16Mb？

Answer 1

是的，通过将环境变量 bootm_low 和 bootm_size 设置为十六进制值，可以在 U-Boot 中配置此值。在您的例子中，它分别是 0x0 和 0x20000000。

请参阅 U-Boot 源代码树中大 README 文件的“环境变量”部分。