考虑以下装饰器函数,它要么返回一个装饰函数,要么返回一个参数化的装饰或函数:
from functools import wraps, partial, update_wrapper
from inspect import signature
def wrapit(func=None, *, verb='calling'):
if func is None: # return a decoratOR
return partial(wrapit, verb=verb)
else: # return a decoratED
@wraps(func)
def _func(*args, **kwargs):
print(f'{verb} {func.__name__} with {args} and {kwargs}')
return func(*args, **kwargs)
return _func
演示:
>>> f = lambda x, y=1: x + y
>>> ff = wrapit(verb='launching')(f)
>>> assert ff(10) == 11
launching <lambda> with (10,) and {}
>>> assert signature(ff) == signature(f)
>>>
>>> # but can also use it as a "decorator factory"
>>> @wrapit(verb='calling')
... def f(x, y=1):
... return x + y
...
>>> assert ff(10) == 11
launching <lambda> with (10,) and {}
>>> assert signature(ff) == signature(f)
类的形式可能看起来像这样:
class Wrapit:
def __init__(self, func, verb='calling'):
self.func, self.verb = func, verb
update_wrapper(self, func)
def __call__(self, *args, **kwargs):
print(f'{self.verb} {self.func.__name__} with {args} and {kwargs}')
return self.func(*args, **kwargs)
但是我们如何让类能够在功能形式具有的“装饰器工厂”模式下运行(由 if func is None: return partial...
实现)
我们如何将这个技巧集成到装饰器类中?
最佳答案
正如评论中所建议的那样,您可以使用 __new__
方法执行此操作:
class Wrapit:
def __new__(cls, func=None, *, verb='calling'):
if func is None:
return partial(cls,verb=verb)
self = super().__new__(cls)
self.func, self.verb = func, verb
update_wrapper(self, func)
return self
def __call__(self, *args, **kwargs):
print(f'{self.verb} {self.func.__name__} with {args} and {kwargs}')
return self.func(*args, **kwargs)
__new__
方法在您尝试实例化一个类时被调用,并且该方法的返回值用作尝试实例化的结果——即使它不是该类的实例!
关于python - 使用一个类同时作为装饰器和装饰器工厂进行操作,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/62379216/