我有一个如下所示的数据框:
a b c d
1 2005-01-01 0 ... ...
2 2005-02-22 1 ... ...
3 2005-04-02 0 ... ...
4 2005-12-01 3 ... ...
5 2006-03-03 0 ... ...
6 2006-06-08 1 ... ...
7 2006-10-11 0 ... ...
8 2006-12-02 4 ... ...
9 2007-03-24 0 ... ...
10 2007-04-06 2 ... ...
11 2008-01-28 0 ... ...
12 2008-08-19 0 ... ...
13 2008-09-12 0 ... ...
14 2008-12-12 2 ... ...
15 2009-05-27 0 ... ...
16 ... . ... ...
我想选择 2005 年的所有行并查看其中有多少行是 0、1、2、3 或 4(例如与列 b 结合)。也许与比例？例如，结果将是:
output:
2005
0 1 2 3 4
20% 20% 20% 20% 20%
我试过 table(year(DF$a), c=DF$b) 但这只会产生所有年份的概览，没有比例或类似的东西。我试着用 %>% 将其通过管道传递到比例函数中，但这不起作用。
有人知道怎么做吗？
您可以使用 table和 proportions获得每年的份额，在这里你可以给margin在 proportions , 在这里 1 , 每行做一次。
proportions(table(format(DF$a, "%Y"), DF$b), 1) * 100
# 0 1 2 3 4
# 2005 50 25 0 25 0
# 2006 50 25 0 0 25
# 2007 50 0 50 0 0
# 2008 75 0 25 0 0
# 2009 100 0 0 0 0
数据:
DF <- structure(list(a = structure(c(12784, 12836, 12875, 13118, 13210,
13307, 13432, 13484, 13596, 13609, 13906, 14110, 14134, 14225,
14391), class = "Date"), b = c(0L, 1L, 0L, 3L, 0L, 1L, 0L, 4L,
0L, 2L, 0L, 0L, 0L, 2L, 0L), c = c("...", "...", "...", "...",
"...", "...", "...", "...", "...", "...", "...", "...", "...",
"...", "..."), d = c("...", "...", "...", "...", "...", "...",
"...", "...", "...", "...", "...", "...", "...", "...", "..."
)), row.names = c("1", "2", "3", "4", "5", "6", "7", "8", "9",
"10", "11", "12", "13", "14", "15"), class = "data.frame")