django - Graphite 烯-django : 'Meta.model' without either 'Meta.fields' or 'Meta.exclude' has been deprecated since 0. 15.0 现在被禁止

Question

我正在尝试使用 django-graphene 返回过滤结果，但它给出了关于 error-message 的错误

class PatientType(DjangoObjectType):
    class Meta:
        model = Patients
        exclude = ('active',)
        interfaces = (relay.Node,)


class PatientsQuery(ObjectType):
    get_patient = graphene.Field(PatientType, id=graphene.Int())
    all_patients = graphene.List(
        PatientType, first=graphene.Int(), skip=graphene.Int(), phone_no=graphene.Int()
    )
    upcoming_appointments = DjangoFilterConnectionField(PatientType)


@permissions_checker([IsAuthenticated, CheckIsOrganizationActive])
def resolve_upcoming_appointments(self, info, **kwargs) -> List:
    d = datetime.today() - timedelta(hours=1)
    settings.TIME_ZONE  # 'Asia/Karachi'
    aware_datetime = make_aware(d)
    res = Patients.objects.filter(appointments__booking_date__gte=aware_datetime,
                                  appointments__booking_date__day=aware_datetime.day,
                                  appointments__status=True)
    if res:
        return res
    return []


class Query(
    organization_schema.OrganizationQuery,
    inventory_schema.MedicineQuery,
    patient_schema.PatientsQuery,
    graphene.ObjectType,
):
    pass

Answer 1

在 filter_fields 中指定 PatientType.Meta 属性为

class PatientType(DjangoObjectType):
    class Meta:
        model = Patients
        exclude = ('active',)
        interfaces = (relay.Node,)
        filter_fields = ["field_1", "field_2"]

或者，您可以在 filter_fields=[] 部分中设置 filterset_class 或 Meta 属性
更多示例可以在文档中找到， GraphenePython- Filtering